Answer:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Explanation:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Answer:
The answer is ligaments!
Explanation:
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A catalyst
please put the correct answer
Catalyst is a type of material that is used to speed up a chemical reaction, such that it is never used up.
The definition of a catalyst is a material that speeds up a chemical process without permanently altering its chemical composition.
The catalytic activity is defined as a chemical interaction between the catalyst and a reactant that produces chemical intermediates that may more easily react with one another or with another reactant to produce the final product that is required.
The catalyst is regenerated during the reaction between the reactants and the chemical intermediates.
The ways in which catalysts and reactants interact vary greatly and are frequently intricate in solid catalysts.
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Clark Grizwald put a neon green blinking tree that weights 2.3 kg on top of his house 50 meters off the ground but he didn't tie it down right. How much velocity does the blinking tree have when it is 2 meters from the ground? Solve
The magnitude of the velocity the blinking tree has when it is 2 meters from the ground is 21.8 m/s.
Conservation of energyTo calculate the velocity of the blinking tree when it is 2 meters from the ground, we can use the principles of conservation of energy.
First, let's determine the potential energy of the tree when it is 50 meters off the ground. The potential energy (PE) can be calculated using the formula:
PE = mgh
Where:
m = mass of the tree (2.3 kg)
g = acceleration due to gravity (9.8 m/s^2)
h = height (50 m)
PE = 2.3 x 9.8 x 50
PE = 1131 J
Next, we can calculate the potential energy of the tree when it is 2 meters from the ground:
PE = mgh
Thus:
PE = 2.3 x 9.8 x 2
PE = 45.04 J
According to the conservation of energy principle:
PE(initial) = PE(final) + KE(final)
1131 J = 45.04 J + KE(final)
Now, let's solve for the kinetic energy (KE) at the final position:
KE(final) = PE(initial) - PE(final)
KE(final) = 1131 J - 45.04 J
KE(final) = 1085.96 J
KE = (1/2)mv^2
1085.96 J = (1/2) x 2.3 kg x v^2
Thus
v^2 = (2 x 1085.96 J) / 2.3 kg
v^2 = 474.76 m^2/s^2
v ≈ 21.8 m/s
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Someone has been shot! We found a blood drop that was measured to be 0.8 mm wide and 2.1 mm long. The drop landed 5.1 feet away. How high up was the person shot?
To determine the height from which a person was shot based on the distance traveled by a blood drop, we can use projectile motion calculations considering the vertical component and apply the equations for the time of flight and vertical distance traveled.
To determine how high up the person was shot, we can use the properties of a projectile motion and the dimensions of the blood drop.
First, convert the distance from feet to meters, as it is a more commonly used unit in physics calculations. 5.1 feet is approximately 1.55 meters.
The blood drop is assumed to follow a parabolic trajectory, where its horizontal and vertical motion are independent. We can focus on the vertical component to determine the height.
The horizontal distance traveled by the blood drop is not relevant to calculating the height.
The vertical distance traveled by the blood drop can be calculated using the equation:
d = ut + (1/2)gt^2
Where:
d is the vertical distance traveled (height),
u is the initial vertical velocity (0 since the drop starts at rest),
t is the time of flight,
g is the acceleration due to gravity (approximately 9.8 m/s^2).
Rearranging the equation, we have:
t = sqrt((2d)/g)
The time of flight can be found using the measured distance, as the horizontal and vertical motion take place simultaneously:
t = distance / horizontal velocity
The horizontal velocity is the horizontal distance divided by the time of flight, which is 1.55 meters divided by the time of flight.
Substitute the time of flight from step 5 into the equation from step 6 and solve for the horizontal velocity.
Now, we know the horizontal velocity, and we can calculate the time it takes for the blood drop to travel from the person to the landing point, which is the horizontal distance divided by the horizontal velocity.
Finally, we can use the time of flight obtained in step 8 and substitute it back into the equation from step 5 to calculate the height.
Please note that this calculation assumes ideal projectile motion without considering factors like air resistance or other variables that may affect the trajectory. Additionally, the size of a single blood drop may not accurately reflect the height from which a person was shot. It is important to consult medical professionals and forensic experts for accurate analysis and interpretation of crime scene evidence.
Therefore, We can use projectile motion calculations with the vertical component and apply the equations for time of flight and vertical distance travelled to determine the height from which a person was shot based on the distance travelled by a blood drop.
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