A 50.0-kg child stands at the rim of a merry-go-round of radius 2.00 m, rotating in such a way that it makes one revolution in 2.09 s. What minimum coefficient of static friction between her feet and the floor of the merry-go-round is required to keep her in the circular path

Answers

Answer 1

Answer:

2.01

Explanation:

First, we need to find the centripetal acceleration.

We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute

Now this speed gotten in rpm will be converted to m/s, to ease the calculation

30 rpm = πdN/60 m/s

30 rpm = (3.142 * 4 * 30)/60

30 rpm = 377.04/60

30 rpm = 6.284 m/s

a(c) = v²/r

a(c) = 6.284²/2

a(c) = 39.49 / 2

a(c) = 19.74 m/s²

F = ma

F = 50 * 19.74

F = 987 N

Also, Normal Force, F(n) =

F(n) = mg

F(n) = 50 * 9.81

F(n) = 490.5

We then use this to find the coefficient of static friction, μ

μ = F/F(n)

μ = 987 / 490.5

μ = 2.01


Related Questions

The intensity of sound is measured on the decibel scale, dB. The equation dB=10 log I represents the decibel level, where I is the ratio of the sound to the human hearing threshold. A noise is 150,000 times greater than the human hearing threshold. Which shows a valid step in the process of finding the decibel level of the noise?

a. 150,000 = 10 log I
b. 15,000 = log I
c. dB = 10 log 150,000
d. 10dB = log 150,000
e. 10/dB= log 150,000

Answers

Answer:

The correct option is  c

Explanation:

From the question we are told that

    The ratio of the noise to human hearing threshold is  [tex]I = 150 000[/tex]

Generally from the equation given we have that

       dB =  10 log I

So

      dB =  10 log 150000  

 

The expression that shows a valid step in the process of finding the decibel level of the noise is dB = 10 log 150,000. Option C is correct

Given the equation for calculating the intensity of sound which is measured in decibel expressed as:

dB=10 log I

where;

I is the ratio of the sound to the human hearing threshold

Given that noise is 150,000 times greater than the human hearing threshold.

Substitute I = 150,000 into the expression above;

dB =  10 log 150,000

Hence the expression that shows a valid step in the process of finding the decibel level of the noise is dB = 10 log 150,000

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Light of wavelength 500 nm illuminates parallel slits and produces an interference pattern on a screen that is 1 m from the slits. In terms of the initial intensity I0, the light's intensity in the interference pattern at a point for which the path difference is 300 nm is

Answers

Answer:

this point we have a destructive inference  m=1

Explanation:

This is an interference exercise, where the light has two possible states one of constrictive interference

            d sin θ = m λ

and another of destructive interference

           d sin θ = (m + ½) λ

the term on the left is the difference in trajectory that tells us that it is worth

            d sin θ = 300 nm = 300 10⁻⁹ m

We can find what type of interference we have by finding m, which must be an integer

             

constructive interference

           m = d sin θ /λ

let's calculate

          m = 300 10⁻⁹ / 500 10⁻⁹

          m = 0.6

this value is not possible because m must be an integer

destructive interference

          m + ½ = d sin θ /λ  

          m = d sin θ /λ  + ½

          m = 0.6 + 0.5

         m = 1.1

that can be approximated to m = 1

this value if possible, so at this point we have a destructive inference

10 POINTS BE FAST
Which statement illustrates how progress in engineering has affected the
natural environment?(please hurry)

A. Modern mining practices provide materials that can be used for
technological advances.

B. Modern mining equipment has improved
the health and safety of
workers.

C. Extracting mineral resources
with modern mining equipment
removes fertile topsoil.

D. Mining companies use modern equipment to extract mineral
resources more efficiently.

hurry please

Answers

Answer:

I think it's c or A hopes this help

please answer True or false

In two square the server earns a point when the opponent catches the ball.​

Answers

true i think?? not 100% because i’m thinking of four square haha

The pendulum consists of two slender rods AB and OC which each have a mass of 3 kg/m. The thin plate has a mass of 10 kg/m2. Determine the location of the center of mass G of the pendulum, then calculate the moment of inertia of the pendulum about an axis perpendicular to the page and passing through G.

Answers

Answer:

the answer is below

Explanation:

The diagram of the problem is given in the image attached.

Mass of rod AB = (0.4 m + 0.4 m) * 3 kg/m = 2.4 kg

Mass of rod OC = (1.5 m) * 3 kg/m = 4.5 kg

Mass of plate = 10 kg/m²[ (π* 0.3²) - (π* 0.1²)] = 2.513 kg

The center of mass is:

[tex]\hat{y}[2.4+2.513+4.5]=(0.75*4.5)+(2.513*0.5)\\\\\hat{y}=0.839\\\\I_{AB}=\frac{1}{12}*2.4*(0.4+0.4)^2= 0.128\ kg/m^2\\\\I_{OC}=\frac{1}{12}*4.5*(1.5)^2= 3.375\ kg/m^2\\\\I_{Gplate}=\frac{1}{2}*(\pi*0.3^2*10)*(0.3)^2-\frac{1}{2}*(\pi*0.1^2*10)*(0.1)^2= 0.126\ kg/m^2\\\\I_{plate}=I_{Gplate}+md^2=0.126+2.513(1.8^2)=8.27\ kg/m^2\\\\I_o=I_{plate}+I_{AB}+I_{OC}\\\\I_{o}=0.128+3.375+8.27=11.773\ kg/m^2 \\\\I_G=I_o-m_{tot}\hat{y}^2\\\\I_G=11.773-(9.413*0.839^2)\\\\I_G=5.147\ kg/m^2[/tex]

A 2.00 kg copper pot is placed on a glass shelf and then one side of the shelf falls so that it becomes angled at 35.0° to the horizontal. The coefficient of static friction between copper and glass is 0.680 and the coefficient of kinetic friction is 0.530. Will the pot slide, and if so, what is its acceleration?​

Answers

Answer:

Explanation: about 2 Mph when it falls and sorry if I’m wrong

it is difficult to walk on a smooth floor why​

Answers

Answer:

because theres is not enough friction so it will be super slippery

Explanation:

come in my free candy van located at Skellerupvej 43, 8600 Silkeborg, Denmark

Answers

Answer:

Did you think you could pull that off-

:I

I live in Japan anyway so.. ウーフ-

For which object would a geologist use carbon-14 dating to determine age?

The bones of animals
Rocks older than 50,000 years old
Types of Sedimentary rocks
Parts of Volcanic rock

Answers

Answer:

B. older than 50,000 years old

hope it helps you

Rocks older than 50,000 years old are objects in which geologists use carbon-14 dating to determine its age.

What is Carbon dating?

This is used to determine age by using the decay to nitrogen of radiocarbon (carbon-14).

Older rocks can have its age determined through the use of carbon-14 which is why option B was chosen.

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Why do hurricanes develop over oceans?
Question 5 options:
The ocean is affected by the Coriolis effect.
The ocean winds blow from north to south.
The warmer ocean adds water vapor to the air mass.
The ocean currents cause air to move toward the land.

Answers

My guess is; The warmer ocean adds water vapor to the air mass.

I'm really sorry if I'm wrong

The warmer ocean adds water vapor to the air mads

What are earth crossing asteroids and how do we monitor them

Answers

Answer:

Earth-crossing asteroid, asteroid whose path around the Sun crosses Earth's orbit. Two groups of such asteroids—Aten and Apollo asteroids—are distinguished by the size of their orbits and how closely they approach the Sun.

Explanation:

Compare the weight of a 60 kg person on the earth with the weight of the same person on
the moon. Then, describe a quick (but very costly) way for dieters
at NASA to lose weight.

Answers

Answer:

Explanation:

The formula for weight is

W = mg, where

W = the weight of the object or person

m = mass of the object or person

g = acceleration due to gravity

Now, we're given the mass of the person to be 60 kd, and thus, the weight of that person would be

W = 60 * 9.81

W = 588.6 N

On the surface of the moon, the weight of the person would be

W = 60 * 1.625

W = 97.5 N

Therefore, the weight of the person on both surfaces are 588.6 and 97.5 respectively

Do clouds have respiration

Answers

Answer:

yes it also does have but not in the exact form but it does 30 percent of respiration to produce rain

i think so, i’m not sure completely but it should have respiration

A slanted surface used to raise an object is a(n)​

Answers

Answer:

Inclined Plane

Explanation:

Which of the following is the best example of Newton’s third law? A. A person riding a bike at a constant speed B. A car accelerating C. Rowing a boat D. An orange rolling off a tray

Answers

Answer:

C; Rowing a boat

Explanation:

Hope this helps!      :3

Plz mark as brainliest!

Chemical reactions and nuclear reactions cause matter to change in different
ways. Which two statements describe how matter changes only in a chemical
reaction?
A. The nuclei of the atoms change.
B. Atoms and their electrons are rearranged.
O C. New atoms and elements are formed.
D. The elements stay the same.

Answers

Answer:

B. Atoms and their electrons are rearranged.

D. The elements stay the same.

Two men, Joel and Jerry, push against a car that has stalled, trying unsuccessfully to get it moving. Jerry stops after 10 min, while Joel is able to push for 5.0 min longer. Compare the work they do on the car.

a. Joel does 75% more work than Jerry.
b. Joel does 25% more work than Jerry.
c. Jerry does 50% more work than Joel.
d. Joel does 50% more work than Jerry
e. None of the above .

Answers

Answer:

the answer is B

Explanation:

5. 3 women push a stalled car. Each woman pushes with a 400N force. What is the mass of the car if the car accelerates at 0.85 m/s??

Answers

Answer:

470.59 kg

Explanation:

The the mass of the car can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{400}{0.85} \\ = 470.58823...[/tex]

We have the final answer as

470.59 kg

Hope this helps you

On what does kinetic energy depend?
a. Mass and velocity b. Gravity and mass c. Gravity and height d.
Velocity and gravity

Answers

Answer:

b

Explanation:

Answer:

Gravity and Mass

Explanation:

Kinetic energy is the energy of something moving. To get a lot of kinetic energy, there has to be a situation where the gravity is moving in the way the object is moving. The heavier the object, the faster it'll move.

Assuming perfect optics, if the smallest feature you can resolve when observing around 660 nm is of angular size 0.04 arcsec, what would the size (in arcsec) of the finest feature you can resolve if you make your observation around wavelength 1320 nm, assuming everything else is the same

Answers

Answer:

The value is [tex]\theta _2 = 0.08 \ arcsec[/tex]

Explanation:

From the question we are told that

   The first wavelength is  [tex]\lambda_1 = 660 \ nm = 660 *10^{-9 }[/tex]

   The  first angular size is  [tex]\theta_1 = 0.04 \ arcsec[/tex]

    The second wavelength is  [tex]\lambda _2 = 1320 \ nm = 1320 *10^{-9 } \ m[/tex]

Generally according to  Rayleigh Criterion we have that

          [tex]\theta= 1.22 * \frac{\lambda }{D}[/tex]

given every other thing remains constant we have that

         [tex]\theta = k * \lambda[/tex]

Here k  represented constant so

         [tex]k = \frac{\theta }{\lambda}[/tex]

=>      [tex]\frac{\theta_1}{ \lambda_1} = \frac{\theta_2}{ \lambda_2}[/tex]

=>      [tex]\frac{\theta_1}{ \theta_2} = \frac{\lambda_1}{ \lambda_2}[/tex]

So

        [tex]\frac{ 0.04}{ \theta_2} =0.5[/tex]

=>     [tex]\theta _2 = 0.08 \ arcsec[/tex]


2. 290 grams of water is to be heated from 24.0% to 100.0°C to make a cup of
tem, how much heat must be added? The specific heat of water is 4.18 J/g•C

Answers

Answer:

92127.2 j

Explanation:

Given that :

Mass of water = 290 g

Specific heat of water (C) = 4.18 j/g.C

Initial Temperature (t1) = 24°C

Final temperature (t2) = 100°C

Using the relation :

Q = mCdt

dt = change in temperature =( 100 - 24)° = 76°C

Q = quantity of heat ; C = specific heat capacity;

m = mass of substance

Q = 290 g * 4.18 j/g.C * 76°C

Q = 92127.2 j

Jill does twice as much work as Jack does and in half the time. Jill's power output is Group of answer choices one-fourth as much as Jack's power output. four times Jack's power output. twice Jack's power output. one-half as much as Jack's power output. the same as Jack's power output.

Answers

Answer:

Second Choice.

Explanation:

Jack's Power = W/t

Jill's Power = 2W/(0.5)*t

2/0.5 = 4

Jill's Power = 4*W/t

Jill's Power is 4 times greater than Jack's

Second Choice

A 52.0-kg woman wearing high-heeled shoes is invited into a home in which the kitchen has vinyl floor covering. The heel on each shoe is circular and has a radius of 0.600 cm. If the woman balances on one heel, what pressure does she exert on the floor?

Answers

Answer:

4.5 × 10^6 Nm

Explanation:

Given that a 52.0-kg woman wearing high-heeled shoes is invited into a home in which the kitchen has vinyl floor covering. The heel on each shoe is circular and has a radius of 0.600 cm. If the woman balances on one heel, what pressure does she exert on the floor?

Let's first calculate the area covered by the heel shoe by using the area of a circle.

Convert cm to m

0.6 / 100 = 0.006

A = πr^2

A = 22/7 × 0.006^2

A = 1.131 × 10^-4 m^2

The force exerted by the woman = mg

Force exerted = 52 × 9.8

Force exerted = 509.6 N

Pressure = force / Area

Pressure = 509.6 / 1.131 × 10^-4

Pressure = 4505853.3 N/m

Therefore, she exerts pressure of 4.5 × 10^6 Nm approximately on the floor.

Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (568 nm) on a double slit with a separation of 0.107 mm. The diffraction pattern shines on the classroom wall 3.5 m away. Calculate the fringe separation between the third order and central fringe.

Answers

Answer:

18.58 mm

Explanation:

Formula for the fringe width is;

β = λL/d

We are given;

λ = 568 nm = 568 × 10^(-9) m

L = 3.5 m

d = 0.107 mm = 0.107 × 10^(-3) mm

β = (568 × 10^(-9) × 3.5)/(0.107 × 10^(-3))

β = 0.01858 m = 18.58 mm

Do dwarf planets has several other bodies in their path orbiting the Sun just as they do?​

Answers

Answer:

No they just orbit the sun

Explanation:

3. Ohm's law is represented by the equation I = V/R. Explain how the current would change if the amount of resistance decreased and the voltage stayed the same.

Answers

Answer:

Current will increase

Explanation:

In Ohm's law the equation for current is current = voltage / resistance.

In order to explain how current is effected when resistance decreases while voltage stays the same, lets represents the situations with some possible inputs.

Let's compare 3 different closed circuits all with a voltage of 10V.

In circuit 1, the resistance is 5 ohm.

In circuit 2, the resistance is 2 ohms.

In circuit 3, the resistance is 1 ohms.

The current of:

Circuit 1 = Voltage / Resistance = 10 V / 5 ohms = 2 Amps

Circuit 2 = Voltage / Resistance = 10V / 2 ohms = 5 Amps

Circuit 3 = Voltage / Resistance = 10V / 1ohm = 10 Amps

As you can see in this representation, as the resistance in a circuit increases while the voltage is constant, the total current is increased.

As the resistance decreases, the amount of current increases.

What is Ohm's law?

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

Ohm's law is represented by the equation

I = V/R

Ohm's Law tells us that the electrical current in a circuit can be calculated by dividing the voltage by the resistance.

As the current change if the resistance is decreased,

In this case, there is a inverse relationship between the two variables. As the resistance increases, the current decreases, provided all other factors are kept constant.  

In other words, the current is directly proportional to the voltage and inversely proportional to the resistance.

As the current is directly proportional to the voltage and inversely proportional to the resistance.

So,

an increase in the voltage will increase the current as long as the resistance is held constant.

Learn more about Ohm's law here:

https://brainly.com/question/14874072

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A source emits sound with a frequency of 18,002 Hz. Both it and an observer are moving toward each other, each with a speed of 130 m/s. What frequency (in Hz) does the observer hear

Answers

Answer:

The frequency heard by the observer is 24,830.35 Hz.

Explanation:

Given;

frequency of the source, Fs = 18,002 Hz

speed of the source, Vs = 130

speed of sound in air, V = 343 m/s

Apply Doppler effect, as the source and the observer move closer to each other, the frequency heard by the observer increases because of decrease in distance.

[tex]f_s = f_o[\frac{v}{v + v_s} ]\\\\[/tex]

where;

f₀ is the frequency heard by the observer

[tex]f_s = f_o[\frac{v}{v + v_s} ]\\\\18,002 = f_o[\frac{343}{343 + 130} ]\\\\18,002 = f_o(0.725)\\\\f_o = \frac{18,002}{0.725} \\\\f_o = 24,830.35 \ Hz[/tex]

Therefore, the frequency heard by the observer is 24,830.35 Hz.

X- rays with a wavelgnth of 0.0700 nm diffract from a crystal. Two adjacne angels of x-ray diffraciton are 45.6 and 21.0 degrees. What is the distance in nm between the atomic planes responsible for the diffraction? (Use 2dcos(θ)=m(λ))

Answers

Answer:

0.15 nm

Explanation:

d = Distance between the atomic planes

m = Order

[tex]\theta_{m}[/tex] = First angle = [tex]45.6^{\circ}[/tex]

[tex]\theta_{m+1}[/tex] = Adjacent angle = [tex]21^{\circ}[/tex]

[tex]\lambda[/tex] = Wavelength = 0.07 nm

From Bragg's relation we know

[tex]2d\cos\theta_{m}=m\lambda[/tex]

[tex]2d\cos45.6^{\circ}=m0.07[/tex]

[tex]2d\cos\theta_{m+1}=(m+1)\lambda[/tex]

[tex]2d\cos21^{\circ}=(m+1)0.07\\\Rightarrow 2d\cos21^{\circ}=m(0.07)+0.07[/tex]

So

[tex]2d\cos21^{\circ}=2d\cos45.6^{\circ}+0.07\\\Rightarrow 2d(\cos21^{\circ}-\cos45.6^{\circ})=0.07\\\Rightarrow d=\dfrac{0.07}{2(\cos21^{\circ}-\cos45.6^{\circ})}\\\Rightarrow d=0.14962\ \text{nm}[/tex]

The distance between the atomic planes is 0.15 nm.

Aner shopping. It took Jacob 18 seconds to push his shopping cart to his car. He was moving at 2 meters per second. His daughter walked beside the cart for one-third of the time it took Jacob to reach his car. How far did Jacob's cart move while his daughter was walking beside Write your answer as a whole number meters​

Answers

Answer:

I am going to answer you just wait a little bit.

Determine the weight of a 5.1 kg scooter that moves with a constant acceleration of 3.0 ms2. (Make sure you use the weight equation: W or Fg = mg)

Answers

Answer:

15.3 sorry if i got it wrong

Explanation:

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