Answer:
v = 0.76 [m/s]
Explanation:
The linear momentum generated by the shot must be calculated. This can be calculated using the following expression.
[tex]P=m*v\\[/tex]
where:
P = linear momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
[tex]P=0.004*380\\P=1.52[kg*m/s][/tex]
Now we can calculate the recoil velocity, because the momentum is equal for the rifle.
[tex]P=m*v\\v = P/m\\v = 1.52/2\\v = 0.76[m/s][/tex]
An object located near the surface of Earth has a weight of a 245 N
object?
• What is the mass of the object?
• What is the weight of the object on Mars where the gravity is
3.72 m/s?
Answer:
The mass of the object is 24.5 kg and weight of the object on Mars is 91.14 N.
Explanation:
Weight of the object on the surface of Earth, W = 245 N
On the surface of Earth, acceleration due to gravity, g = 10 m/s²
Weight of an object is given by :
W = mg
m is mass
[tex]m=\dfrac{W}{g}\\\\m=\dfrac{245\ N}{10\ m/s^2}\\\\=24.5\ kg[/tex]
So, the mass of the object is 24.5 kg
Acceleration due to gravity on Mars, g' = 3.72 m/s²
Weight of the object on Mars,
W' =mg'
W' = 24.5 kg × 3.72 m/s²
= 91.14 N
So, the weight of the object on Mars is 91.14 N.
Given the data in the question;
Weight of object; [tex]W = 245N[/tex]
What is the mass of the object.Weight the measure of the force of gravity pulling down on a particle or object.
It is expressed as:
[tex]W = m* g[/tex]
Where m is mass of the object and g is acceleration due to gravity { Acceleration due gravity of Earth [tex]g_{earth} = 9.8m/s^2[/tex] }
We substitute our values into the equation
[tex]245N = m * 9.8m/s^2\\\\245kg.m/s^2 = m * 9.8m/s^2\\\\m = \frac{245kg.m/s^2}{9.8m/s^2} \\\\m = 25kg[/tex]
Therefore, mass of the object located near the Earth surface is 25kg
Weight of the object on Mars where the gravity [tex]3.72m/s^2[/tex]
So on planet Mars; [tex]g = 3.72m/s^2[/tex], we know that mass of the object is [tex]25kg[/tex]
We substitute into our equation
[tex]W = m* g[/tex]
[tex]W = 25kg * 3.72m/s^2\\\\W = 93kg.m/s^2\\\\W = 93N[/tex]
Therefore, the weight of the object on Mars with the given gravity is 93 Newtons.
Learn more: https://brainly.com/question/23245710
A plumb bob is hanging from the ceiling of a car. If the car moves with an acceleration a, what is the angle made by the string with the vertical?
Answer:
[tex]\theta=\tan^{-1}\dfrac{a}{g}[/tex]
Explanation:
Here we are assuming that the car is moving in a straight line and is traveling on a smooth surface. When the car is moving with acceleration [tex]a[/tex] the bob moves in the opposite direction with the same acceleration. Gravity is acting on the bob so it is experiencing an acceleration of [tex]g[/tex] downwards.
The angle between the acceleration [tex]a[/tex] and the acceleration due to gravity [tex]g[/tex] is
[tex]\theta=\tan^{-1}\dfrac{a}{g}[/tex].
How many hydrogen and carbon atoms in a diamond
Answer:
Explanation:
Thus, total 4+4=8 C atoms are present per unit cell of diamond. Carbon has an electronic arrangement of 2,4. In diamond, each carbon shares electrons with four other carbon atoms - forming four single bonds.
Fig. 2.1 shows the extension-load graph for a spring.
extension
06
load
Fig. 2.1
Dint P is the limit of proportionality.
:) (0) Name the law obeyed by the spring from the origin to P.
[1]
(ii) Describe two features of the graph which show that the law is obeyed.
2.
[2]
-) On Fig. 2.1, sketch a possible continuation of the graph when the spring is loaded
beyond the limit of proportionality.
Answer:
(1) Hooke's law
(2) a) Extension is directly proportional to the applied load
b) The starting point of the graph is the origin (0, 0) or absence of load, no extension
Explanation:
(1) The law obeyed by the spring is known as Hooke's law which states that the extension or compression, x, of a spring proportional to the applied force, F
F = -k × x
Where;
k = The spring constant
(2) Given that the law mathematically is F = -k × x
The two features of the graph that show that the law is obeyed are;
a) The extension increases as the load is increased
b) The extension is zero when the there is no applied load.
The density of a substance is 3.4 g cm-3. Its relative density relative to another substance is 2.0. what is the density of the second substance?
Answer:
1.7 g/cm³
Explanation:
Given that:
Density of substance = 3.4 g/cm³
Relative density to another substance = 2
Density of second substance=?
Let density of second substance = x
Relative density = density of substance / density of second substance
Relative density = density of substance / x
2.0 = 3.4g/cm³ / x
2 * x = 3.4 g /cm³
x = 3.4 g/cm³ ÷ 2
x = 1.7 g/cm³
What is the difference between a vigorous sport and vigorous recreation ?
Answer:
Explanation:El ejercicio vigoroso previene en mayor medida el síndrome metabólico (un conjunto de enfermedades que aumentan el riesgo cardiovascular )
mientras que una reacción vigorosa se produce entre el aluminio y el gas cloro. Como consecuencia de la gran cantidad de energía liberada se producen luz y calor
A wagon moving down the road has 2000 kg m/s of momentum. Then a 500-kg bag of feed with no velocity is added to the wagon. What is the new momentum of the wagon with the feed bag in kg m/s?
Answer:
The new momentum of the wagon with the feed bag is (also) 2,000 kg·m/s
Explanation:
The given momentum of the wagon = 2000 kg·m/s
The mass of the added bag = 500 kg
The initial velocity of the bag of feed = 0 m/s
Therefore, by the conservation of momentum principle, we have;
The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon = The new momentum of the wagon with the feed bag
Which gives;
The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon = 2,000 kg·m/s + 500 kg × 0 = 2,000 kg·m/s = The new momentum of the wagon with the feed bag
Therefore, the new momentum of the wagon with the feed bag = 2,000 kg·m/s.
A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling.
Answer:
35 m/s
hope this helpedd
Explanation:
Kinetic Energy 1 upon 2 into mass into velocity square
1 upon 2 into 180 into velocity square=110250
v^2=110250 multiple by 2 and divided by 180
And take square root
If you push an 5 N object 2 m and then push a 10 N object 2 m. Which is TRUE?
You do the same amount of work.
You do more work when you move the 10 N object.
You are more powerful when you move the 5 N object
O You use the same amount of force.
Answer:
Explanation:
You don't do the same amount of work. The work formula is F*d = W
W = work
F = force
d = the distance moved.
So you do more work when you move the 10N object because the Force (F) has doubled.
What does the unit Newton equal to in Sl units?
Answer:
Newton is the SI unit of force
Explanation:
A force of 1 Newton is said to be applied when an object of 1kg mass is transferred into motion at 1m/s.
The Newton is the force that accelerates 1 kilogram of mass at the rate of 1 meter per second^2.
In SI base units, 1N = 1 kg-m/s^2 .
It took a bulldozer 62,000 J of work to move a rock 30 m. It took 5 minutes. How much force did the bulldozer have to apply?
A- 2066.6 N
B- 413.33 N
C- 12,400 N
D- 10,333.33 N
Answer:
A (2066,6 N)
Explanation:
Use the Work formula
62.000J = F . 30
62.000/30 = 2066,6 N
The amout of time it took to move the rock doesn´t matter at all.
It is called a distraction variable, We don´t need it to solve the problem it is there just to confuse.
Which best describes reflection and refraction?
In both reflection and refraction, rays pass through a boundary.
In both reflection and refraction, rays bounce off a boundary.
In reflection, rays bounce off a boundary, and in refraction, rays pass through a boundary.
In refraction, rays bounce off a boundary, and in reflection, rays pass through a boundary.
Answer:
The correct answer is the third option
Explanation:
To reflect means to bounce off. When an incoming ray (called incident ray) gets to a boundary and bounces off the boundary, that is referred to as reflection. However, when an incident ray passes through the boundary and it causes a change in the direction of propagation of the wave, that is referred to as refraction. Thus, the correct option, as explained above, is; In reflection, rays bounce off a boundary, and in refraction, rays pass through a boundary.
Answer:
c
Explanation:
on edge 2020
uh guys so i forgot everything that i took in physics and now i a question, whats p=mv
p stands what?
Answer:
P is momentum.
Explanation:
Brainliest Please!!?!!
- ElizabethKate.
A force of 10N is making an angle of 30
with the horizontal. Its vertical component
will be;
Explanation:
The vertical component = 10sin30° = 5.0N.
A helicopter flies over the arctic ice pack at a constant altitude, towing an airborne 137-kg laser sensor that measures the thickness of the ice (see the drawing). The helicopter and the sensor both move only in the horizontal direction and have a horizontal acceleration of magnitude 2.63 m/s2. Ignoring air resistance, find the tension in the cable towing the sensor. Incorrect: Your answer is incorrect.
Answer:
The value is [tex]T = 1702.91 \ N[/tex]
Explanation:
From the question we are told that
The mass of the laser sensor is [tex]m = 137 \ kg[/tex]
The horizontal acceleration of the helicopter and the sensor is [tex]a = 2.63 \ m/s^2[/tex]
Generally the net force on the cable is
[tex]F = T - W = ma[/tex]
Here W is the weight of the sensor which is evaluated as [tex]W = m * g = 137 * 9.8 = 1342.6 \ N[/tex]
So
[tex]T - 1342.6 = 137 * 2.63[/tex]
=> [tex]T = 360.31 + 1342.6[/tex]
=> [tex]T = 1702.91 \ N[/tex]
An unknown material, m1 = 0.41 kg, at a temperature of T1 = 86 degrees C is added to a Dewer (an insulated container) which contains m2 = 1.7 kg of water at T2 = 22 degrees C. Water has a specific heat of cw = 4186 J/(kg⋅K). After the system comes to equilibrium the final temperature is T = 30.3 degrees C.
Complete Question
An unknown material, m1 = 0.41 kg, at a temperature of T1 = 86 degrees C is added to a Dewer (an insulated container) which contains m2 = 1.7 kg of water at T2 = 22 degrees C. Water has a specific heat of cw = 4186 J/(kg⋅K). After the system comes to equilibrium the final temperature is T = 30.3 degrees C.
Part (a) Input an expression for the specific heat of the unknown material.
Part (b) What is the specific heat in J/(kg⋅K)?
Answer:
a
[tex]c = \frac{m_2 * c_w (T - T_2)}{m_1 * (T_1 - T) }[/tex]
b
[tex]c = 2587.14 \ J /(kg \cdot K)[/tex]
Explanation:
From the question we are told that
The mass of the material is [tex]m_1 = 0.41 \ kg[/tex]
The temperature is [tex]T_1 = 86 ^oC[/tex]
The mass of water is [tex]m_2 = 1.7 \ kg[/tex]
The temperature of water is [tex]T_2 = 22^oC[/tex]
The specific heat of water is [tex]c_w = 4186 \ J/(kg\cdot K)[/tex]
The temperature of the system is [tex]T= 30 .3^o C[/tex]
Generally heat lost by the unknown material = heat gained by water
Generally the heat gained by water is mathematically represented as
[tex]Q_2= m_2 * c_w (T - T_2)[/tex]
=> [tex]Q_2= 1.7 * 4186 (30.3 - 22)[/tex]
=> [tex]Q_2= 59064.46 \ J[/tex]
Generally the heat lost by the unknown material is mathematically represented as
[tex]Q_1= m_1 * c* (T_1 - T)[/tex]
[tex]m_2 * c_w (T - T_2) = m_1 * c* (T_1 - T)[/tex]
=> [tex]c = \frac{m_2 * c_w (T - T_2)}{m_1 * (T_1 - T) }[/tex]
Here c is the specific heat capacity of the unknown material
=> [tex]Q_1= 0.41 * c (86 - 30.3)[/tex]
=> [tex]Q_1= 22.83 c[/tex]
So
[tex]59064.46 = 22.83 c[/tex]
=> [tex]c = \frac{59064.46 }{ 22.83}[/tex]
=> [tex]c = 2587.14 \ J /(kg \cdot K)[/tex]
HELP ASAP!!!!!!! PLEASE WILL GIVE BRAINLIEST
What is a selectively permeable membrane?????????????
Answer:
It is that kind of permeable membrane that allows certain molecules to pass through. Not every molecules can pass through it
Explanation:
Solve ASAP please!!!
Which of these best describes science?
A-Science is the study of fundamental problems such as existence, values, and reason.
B-Science is the collection of all living things on Earth.
C-Science is a body of knowledge and a process of discovery that allows people to understand the natural
world.
D-Science is the practice of diagnosing, treating, and preventing disease.
What is the velocity of a car with a momentum of 100 kg*m/s and a mass of 35kg?
Answer:
2.86 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{p}{m} \\ [/tex]
p is the momentum
m is the mass
From the question we have
[tex]v = \frac{100}{35} = \frac{50}{7} \\ = 2.857142...[/tex]
We have the final answer as
2.86 m/sHope this helps you
Mr Chichester is driving his dark blue camaro to a REO Speedwagon concert. He is driving 15 m/s when he realizes he is going to be late to his favorite band so he slams on the gas for 10s and reaches a final velocity of 45 m/s. How far did Mr. Chichesters travel during this 10s?
Answer:
300m
Explanation:
step one
given data
initial speed u= 15m/s
final speed v= 45m/s
time taken to attain final speed= 10seconds
Step two:
Let us first solve for the acceleration
a= Δv/t
a= 45-15/10
a=30/10
a= 3m/s
applying the equation of motion
[tex]v^2=u^2+2as[/tex]
substituting our given data
[tex]45^2+15^2+2*3*s\\\\2025=225+6s\\\\[/tex]
collect like terms
2025-225=6s
1800=6s
divide both sides by 6
s=1800/6
s=300m
The ball as launched horizontally off a 200m cliff. The initial velocity is 40m/s.
Find the time it takes to hit the ground.
Find the RANGE, distance traveled horizontally.
Find the final vertical velocity.
Answer:
a. 6.39 s b. 255.6 m c. 62.6 m/s
Explanation:
a. Find the time it takes to hit the ground.
Using y = ut + 1/2gt² where y = height of cliff = 200 m, u = initial vertical velocity of ball = 0 m/s, g = acceleration due to gravity = 9.8 m/s² and t = time taken for ball to hit the ground.
So, substituting the values of the variables into the equation, we have
200 m = 0 m/s × t + 1/2 × 9.8 m/s² × t²
200 m = 0 + (4.9 m/s²)t²
200 m = (4.9 m/s²)t²
dividing both sides by 4.9 m/s², we have
t² = 200 m ÷ 4.9 m/s²
t² = 40.82 s²
taking square root of both sides, we have
t = √(40.82 s²)
t = 6.39 s
b. Find the RANGE, distance traveled horizontally.
The range is the horizontal distance traveled by the ball, R = vt where v = horizontal velocity of ball = 40 m/s and t = time taken for ball to hit the ground = 6.39 s
So, R = vt
= 40 m/s × 6.39 s
= 255.6 m
c. Find the final vertical velocity.
Using v = u - gt where u = initial vertical velocity of ball = 0 m/s, v = final velocity of ball, g = g = acceleration due to gravity = 9.8 m/s² and t = time taken for ball to hit the ground = 6.39 s.
So, substituting the values into the equation, we have
v = 0 m/s - 9.8 m/s² × 6.39 s
v = -62.62 m/s
v ≅ -62.6 m/s
What is the general equation for a double-displacement reaction?
Ab -> A+B
A + BX -> B + AX
AX + BY -> AY + BX
A + B -> AB
Explanation:
I know its AX+BY--->AY+BX
what is meant by momentum?
Answer:
Im afraid i need to to know more on what your asking, are you asking what is momentum?
Explanation:
Because therefore it is the quantity of motion of a moving body, measured as a product of its mass and velocity to the state of motion
or
p = mv
I hope this helps and have a good day, or to best that you can make it <33
Answer:
Momentum can be defined as "mass in motion "OrMomentum is how we measure mass that is in motion ORMomentum,product of mass of particle and its velocityExplanation:
Please mark my answer as a brainliest. Please follow me. ❤❤❤❤❤if the angle of refraction is 20 degrees what is the angle of incidence
Answer:
13.1
Explanation:
that's what I'm gonna go with, but u can research more
1.
A car is moving in a circle or radius r = 25 meters, in a parking lot at 10 m/s. What is the car's
centripetal acceleration?
In pulling two identical carry-on bags through the airport, Mr. Myers and his 13 year old grandson, Vincent, do the same amount of work. Who has to use a greater force between gates?
Answer:
Mr Myers and his son use the same force to pull the bags between the gates
Explanation:
The work done by Mr. Myers in pulling the carryon bags = The work done by his 13 year old grandson in pulling the identical bag
Let F₁ represent the force used by Mr Myers, and let F₂ represent the force F₂ used by his grandson
Let d represent the distance through the gate
Therefore, given that Work done, W = Force, F × Distance, we have;
The work done by Mr Myers between the gates, W₁ = F₁ × d
The work done by his grandson between the gates, W₂ = F₂ × d
Where, the work done by both Mr Myers and his grandson are equal, we have;
W₁ = W₂ and therefore, F₁ × d = F₂ × d, which gives;
F₁ = F₂, the force used by both Mr Myers and his son between the gates are equal.
A car is moving along a straight horizontal road. The car has 1.6MJ of kinetic energy. The car accelerates for 20s until the kinetic energy of the car increases to 2.5MJ. What is the minimum average power developed by the car engine for this acceleration?
Answer:
P = 45 [kW]
Explanation:
We must find the difference in kinetic energy during the 20 seconds.
[tex]D_{kE}=2.5-1.6\\D_{kE}=0.9[MJ][/tex]
Power is defined as the relationship between energy over time.
[tex]P=D_{kE}/t\\P=0.9/20\\P=0.045[MW] or 45 [kW][/tex]
A stone is thrown vertically upwards with an initial velocity 20m/s. Find the maximum height it reaches and the time taken by it to reach the height.
(g= 10m/s)
who gives answer with explanation i will make him braillint
Answer:
The maximum height it reaches will be 20 m.
The time taken by it to reach the height will be: t = 2 seconds.
Explanation:
We know the equation of the motion under gravity
v² - u² = 2gs
u = initial velocity = 20 m/s
v = final velocity = 0 m/s
[tex]s\:=\:h_{max}[/tex]
so
[tex]v^{2} \:-\:u^{2} \:=\:2gs[/tex]
substituting u = 20 m/s, v = 0 m/s, g = -10 and [tex]s\:=\:h_{max}[/tex]
[tex]\left(0\right)^2-\:\left(20\right)^2=\:2\left(-10\right)\times h_{max}[/tex]
[tex]2\left(-10\right)\times h_{max}=-400[/tex]
[tex]\frac{2\left(-10\right)h_{max}}{-20}=\frac{-400}{-20}[/tex]
[tex]\:h_{max}=20[/tex] m
Therefore, the maximum height it reaches will be 20 m.
We know the equation
u = gt
substitute u = 20, g = 10
20 = 10 × t
t = 20/10
t = 2 seconds
Therefore, the time taken by it to reach the height will be: t = 2 seconds.
Please help me with this question please
help!!! if it’s blurry click on it and zoom in but i need to know the net forces!!!
Answer:
the net force is 330N
Explanation:
Answer:
270N to the left
Explanation:
Since the 3 individual forces are all parallel to each other and effect the x-axis, you can add and subtract them to find the net force.
The three forces are:
200 N to the LEFT
300 N to the LEFT
230 N to the RIGHT
First, add up any multiples of forces with the same direction. Basically, add up all the forces going LEFT and all going RIGHT.
200 N + 300 N = 500 N LEFT
230 N RIGHT
In order to find resultant magnitude you must now subtract the larger force from the smaller force. The resultant direction will be in the direction of the larger force.
Magnitude of Net Force: 500 N - 230 N = 270 N
Net Force Direction: Direction of larger force: Direction of 500N force: LEFT
