[tex]\sf{\underline{\underline{\qquad \clubsuit \: Given :\clubsuit\qquad}}} \\ [/tex]
Force = 50 NArea = 5 m²[tex]\sf{\underline{\underline{\qquad \clubsuit \: To \:Find :\clubsuit\qquad}}} \\ [/tex]
The pressure exerted by the fluid = ?[tex]\sf{\underline{\underline{\qquad \clubsuit \: Solution :\clubsuit\qquad}}} \\ [/tex]
[tex]:\implies\sf Pressure = \dfrac{Force}{Area} \\ \\ \\ [/tex]
[tex]:\implies\sf Pressure = \dfrac{50}{5} \\ \\ \\ [/tex]
[tex]:\implies \underline{ \boxed{\sf Pressure = 10 \:pascal }}\\ \\ \\ [/tex]
[tex]\therefore{\underline{\textsf{The pressure exerted by the fluid is \textbf{10 pascal}}}}. \\ [/tex]
Two copper spheres are currently 1.2 meters apart. One sphere has a charge of +2.2 x 10-4 C and the other has a charge of -8.9 x 10-4C.
What is the force between the charged spheres?
Is the force attractive or repulsive?
Answer:
The force between the charged spheres is 1,223.75 N
The force is attractive because opposite charges mutually attract.
Explanation:
Coulomb's Law
The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Expressing the above as a formula:
[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]
Where:
[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]
q1, q2 = the objects' charge
d= The distance between the objects
The copper spheres have charges of:
[tex]q_1=+2.2\cdot 10^{-4}\ c[/tex]
[tex]q_2=-8.9\cdot 10^{-4}\ c[/tex]
Note the charges have opposite signs.
They are separated by d=1.2 m
Applying Coulomb's formula:
[tex]\displaystyle F=9\cdot 10^9\frac{2.2\cdot 10^{-4}\cdot 8.9\cdot 10^{-4}}{1.2^2}[/tex]
[tex]\displaystyle F=9\cdot 10^9\frac{1.958\cdot 10^{-7}}{1.44}[/tex]
F = 1,223.75 N
The force between the charged spheres is 1,223.75 N
The force is attractive because opposite charges mutually attract.
Which statement describes the factors that affect the force of friction? Question 2 options: Friction is always the same no matter what Friction increases as the normal force (weight) increases, and also depends on the surface Friction is greater when objects are barely touching Friction is greater on slippery surfaces
Answer:
(b) Friction increases as the normal force (weight) increases, and also depends on the surface
Explanation:
The coefficient of friction relates the normal force between surfaces to the friction force opposing motion. The coefficient depends on the surface.
The appropriate choice is ...
Friction increases as the normal force (weight) increases, and also depends on the surface
The energy flow per unit time per unit area (S) of an electromagnetic wave has an average value of 310 mW/m2. The maximum value of the magnetic field in the wave is closest to:
Answer:
5.096*10^-8
Explanation:
Given that
The average value of the electromagnetic wave is 310 mW/m²
To find the maximum value of the magnetic field the wave is closest to, we say
Emax = √Erms
Emax = √[(2 * 0.310 * 3*10^8 * 4π*10^-7)]
Emax = √233.7648
Emax = 15.289
Now, with our value of maximum electromagnetic wave gotten, we divide it by speed of light to get our final answer
15.289 / (3*10^8) = 5.096*10^-8 T
Suffice to say, The maximum value of the magnetic field in the wave is closest to 5.096*10^-8
hello what is a major theme of this speech?
When using an open flame or hot plate,
which of the following should be used
as a safety precaution to avoid burns?
A. test tube
B. beaker
C. hot pad or mit
D. safety goggles
The gravity on Earth is 9.8m/s2, the mass of a bowling ball is about 5kg. What is the weight of the bowling ball on the Earth?
Answer:
yo can someone answer i need this
Explanation:
a girl weighing 350N runs up hill upto 5m in 20sec. calculate her work done and power
Work done against gravity becomes potential energy of the object-Earth system. Its given by:
W = Ep
W = mgh but weigh(w) = mg
W = wh
W = 350 N × 5 m
W = 1750 JPower is the amount of energy transferred or converted per unit time. This is:
P = W/t
P = 1750 J / 20 s
P = 87.5 WDefine each of the three heat transfer methods:
Conduction
Convection
Radiation
A ball is thrown with a speed of 100 ft/s in a direction of 30 degrees above the horizontal. determine the horizontal distance in m, the time of flight, and the height to which it rises..Note: you have to label your answer and final answer must be two decimal place
Answer:
Horizontal distance covered is 270.63ft
Time of flight is 3.125secs
Height to which it rises is 39.06feet
Explanation:
The horizontal distance covered is the range;
Range = U²sin2theta/g
Range = 100²sin2(30)/32
Range = 10000sin60/32
Range = 10000(0.8660)/32
Range = 8660/32
Range = 270.625ft
Hence the horizontal distance covered is 270.63ft
The time of flight is expressed using the formula;
T = 2Usin theta/g
g is the acceleration due to gravity
T = 2(100)sin30/32
T = 200(0.5)/32
T = 100/32
T = 3.125secs
Hence the time of flight is 3.125secs
Maximum height H = u²sin²theta/2g
H = 100²(sin30)²/2(32)
H = 10000(0.5²)/64
H = 10000(0.25)/64
H = 2500/64
H = 39.0625
Hence the height to which it rises is 39.06feet
A runaway train car that has a mass of 15,000 kg travels at a speed of 5.4 m/s down a track. Compute the time required for a force of 1500 N to bring the car to rest.
The 1500 N force would need to act in the direction opposite the train car's movement, so if we take the current direction it's moving in to be positive, we have by Newton's second law
-1500 N = (15,000 kg) a → a = -0.10 m/s²
If t is the time it takes for the train to come to rest, then
-0.10 m/s² = (0 - 5.4 m/s) / t
t = (5.4 m/s) / (0.10 m/s²) → t = 54 s
How can you measure the strength of any electric field?
Answer:
The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.
Explanation:
Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.
please write the definition of instantaneous speed, velocity and acceleration and solve problems on them please show workings
Answer:
instantaneous speed: The instantaneous speed is the speed of an object at a particular moment in time. And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time.
velocity: the speed of something in a given direction.
acceleration: a vehicle's capacity to gain speed within a short time.
solve problems: Problem solving consists of using generic or ad hoc methods in an orderly manner to find solutions to problems.
Explanation:
7. an electron with initial kinetic energy of 6.0 eV encounters a barrier with height 11.0 eV. What is the probability of tunneling if he width of he barrier is a. 0.80 nm b. 0.40 nm.
Explanation:
In quantum tunneling through a brier, the energy of the tunneled particle is same but the probability amplitude is decreased.
The expression for the probability of tunneling is expressed as follows:
[tex]T=16 \frac{E}{U_{0}}\left(1-\frac{E}{U_{0}}\right) e^{-2 \sqrt{\frac{2 m\left(U_{0}-E\right)}{h}} L}[/tex]
Here, T is the transmission probability; E is the kinetic energy, U_{0} is the barrier height, $m$ is the mass of the electron, and L is the width of the barrier.
Two equal forces act at the same time on the same motionless object, but in opposite directions. Which statement best describes the object’s resulting motion? A. The object will accelerate. B. The object will change direction. C. The object will move at a constant speed. D. The object will remain motionless.
Answer:
D
Explanation:
The object will remain motionless(i just need points)
it is difficult to smooth floor why
Complete question is:
It's is difficult to walk on a wet floor than a smooth floor. Why?
Answer:
Because friction on wet floor is far lesser than on a smooth floor
Explanation:
On wet surfaces, the friction is far lesser than on smooth surfaces and thus the grip between the bottom of your shoes/feet and the ground is very very small and as such walking on the wet surface becomes more difficult. Whereas on Smooth surfaces, there is plenty of friction and as a result, there is enough grip between the bottom of your shoes/feet and the ground thereby making walking far easier.
please help!!!
In an electric motor, how do the permanent magnets and the electromagnet
interact?
PLEASE ANSWER FAST
A. The electromagnet causes the permanent magnets to reverse
poles.
B. The permanent magnets reverse the current in the electromagnet.
C. The electromagnet reverses the current in the permanent
magnets.
D. The permanent magnets cause the metal loop in the
electromagnet to turn.
if you don’t know don’t answer
The correct asnwer is D. The permanent magnets cause the metal loop in the
electromagnet to turn.
In an electric motor, the permanent magnets cause the metal loop in the
electromagnet to turn. So, option (D) is correct.
What is electric motor?An electrical device that transforms electrical energy into mechanical energy is an electric motor. The majority of electric motors work by creating force in the form of torque imparted to the motor shaft through the interplay of the magnetic field of the motor and electric current in a wire winding.
In an electric motor, their remains a permanent magnet to produce constant magnetic field. When electric current is passed through the conducting loop, it acts ling electromagnet and begins to rotate. Thus an electric motor works. Hence, option(D) is correct.
To find more about electric motor, refer the link:
https://brainly.com/question/15409160
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The charge on an electron is
Answer:
there is a negative charge on electron.
Explanation:
football or basketball which one is easier to get you offers
Answer:
basketball
Explanation: cause it is
Answer:
It honestly depends on which one you're better at.
Explanation: I mean that's what I think.
A typical donation of whole blood is equal to a pint (473 ml). If the average density of blood rhoBLOOD = 1060 kg/m^3, what is the mass of donated blood?
a. 5.01 kg
b. 0.501 lb
c. 0.501 kg
d. 0.501 g
e. 5.01 g
Answer:
c. 0.501 kg
Explanation:
Given;
volume of the denoted blood, V = 473 ml = 0.000473 m³
density of the denoted blood, ρ = 1060 kg/m³
The mass of donated blood is given as;
mass of the donated blood = density of the denoted blood x volume of the denoted blood
m = 1060 x 0.000473
m = 0.501 kg
Therefore, the mass of donated blood is 0.501 kg
Identical particles are placed at the 50-cm and 80-cm marks on a meter stick of negligible mass. This rigid body is then mounted so as to rotate freely about a pivot at the 0-cm mark on the meter stick. If this body is released from rest in a horizontal position, what is the angular speed of the meter stick as it swings through its lowest position
Answer:
5.35 rad/s
Explanation:
From the question, we are toldthat an Identical particles are placed at the 50-cm and 80-cm marks on a meter stick of negligible mass. This rigid body is then mounted so as to rotate freely about a pivot at the 0-cm mark on the meter stick.
Solving this question, the potential energy of the particles must equal to the Kinectic energy i.e
P.E=K.E
Mgh= m½Iω²-------------eqn(*)
Where M= mass of the particles
g= acceleration due to gravity= 9.81m/s^2
ω= angular speed =?
h= height of the particles in the stick on the metre stick= ( 50cm + 80cm)= (0.5m + 0.8m)= 130cm=1.3m
If we substitute the values into eqn(*) we have
m×9.81× (1.3m)= 1/2× m×[ (0.5m)² + [(0.8m)²]× ω²
m(12.74m²/s²)= 1/2× m× (0.25+0.64)× ω
m(12.74m²/s²)= 1/2× m× 0.89× ω²
We can cancel out "m"
12.74= 1/2×0.89 × ω²
12.74×2= 0.89ω²
25.48= 0.89ω²
ω²= 28.629
ω= √28.629
ω=5.35 rad/s
Hence, the angular speed of the meter stick as it swings through its lowest position is 5.35 rad/s
Mark walked 2 miles east than 1 mile north how would you determine his total displacement
They could determine it by counting their total amount of miles mark went by the directions he went to walk those miles.
To celebrate a victory, a pitcher throws her glove straight upward with an initial speed of 5.3 m/s. How long does it take for the glove to reach its maximum height
Hello!!
For the maximum height the final velocity is zero, because can't up more.
Then, use the formula:
V = Vi + gt
Replacing, we have:
0 m/s = 5,3 m/s + (-9,8 m/s² * t)
0 m/s - 5,3 m/s = -9,8 m/s² * t
(-5,3 m/s) / -9,8 m/s² = t
t = 0,54 s
The time it will take to reach the maximum height is 0,54 seconds.
How has the magnet affected the block of material next to it?
A. The domains in the end of the block farthest from the magnet are aligned with its magnetic field.
B. The domains in the end of the block closest to the magnet are aligned with its magnetic field.
C. The domains in the center of the block are aligned with the magnetis magnetic field
D. The domains in the entire block are aligned with the magnets magnetic field
Answer: (APE X) B
Explanation: I am taking it and I just got it right
The magnetic characteristics of a substance are determined by the magnetic moments of its atoms, the domains which are closest to the magnet are aligned with its magnetic field, hence option b is correct.
What is the effect of a magnet?Long-range alignments of magnetic moments in ferromagnetic materials, known as domains, include magnetic moments that all point in the same direction.
This indicates that the atoms' individual magnetic moments are lined up with one another and pointing in the same general direction.
Therefore, a magnetic substance will get magnetized if it is placed close to a magnet. Magnetism is the name for this kind of electricity, hence option b is correct.
Learn more about the magnet, here:
https://brainly.com/question/10666129
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A football quarterback throws a football for a long pass. While in the motion of throwing, the quarterback moves the ball , starting from rest, and completes the motion in . Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass
This question is incomplete, the complete question is;
A football quarterback throws a 0.408 kg football for a long pass. While in the motion of throwing, the quarterback moves the ball 1.909 m, starting from rest, and completes the motion in 0.439 s. Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass ;
a) F_throw = 8.083 N
b) F_throw = 9.181 N
c) F_throw = 2.284 N
d) F_throw = 16.014 N
e) None of these is correct
Answer:
the quarterback applied a force of 8.083 N to the ball during the pass
so Option a) F_throw = 8.083 N is the correct answer
Explanation:
Given that;
m = 0.408 kg
d = 1.909 m
u = 0 { from rest}
t = 0.439 s
Now using Kinetic equation
d = ut + 1/2 at²
we substitute
1.909 = (0 × 0.439) + 1/2 a(0.439)²
1.909 = 0 + 0.09636a
1.909 = 0.09636a
a = 1.909 / 0.09636
a = 19.8111 m/s²
Now force applied will be;
F = ma
we substitute
F = 0.408 × 19.8111
F = 8.0828 ≈ 8.083 N
Therefore the quarterback applied a force of 8.083 N to the ball during the pass
so Option a) F_throw = 8.083 N is the correct answer
which law of thermodynamics would be violated if heat were to spontaneously flow between two abject which are in thermal equilibrium?
Answer:
The law zero of thermodynamics.
Explanation:
The law zero of thermodynamics, which tells us that heat flows from a body at a higher temperature to another body with lower temperature, when the heat transfer is zero, it is said that the two bodies are in thermal equilibrium, their temperatures are equal
what is the shallowest part of the ocean ecosystem is called
Answer:
intertidal zone.
the shallowest part of the ocean ecosystem, where the ocean floor os covered and uncovered as the tide goes in and out. Plankton. the organisms that float on the water in aquatic ecosystems and are unable to swim.
how much work is needed to move an object 20 meters with 40 newtons of force?
Answer: c I think is the answer
Explanation:
Car 1 drives 20 mph to the south, and car 2 drives 30 mph to the north. From
the frame of reference of car 1, what is the velocity of car 2?
Answer:
10 mph faster than car 1 is going
Explanation:
Consider a box with the same mass and velocity instead sliding without friction toward the incline. How does this object's kinetic energy before the incline compare to the sphere
Answer:
Object's kinetic energy is high on frictionless medium.
Explanation:
There is a great difference in object's kinetic energy which is present between sliding with friction and sliding without friction because friction decreases the speed of an object so if an object moves on the frictionless medium, it moves and covers more distance and we can say that the object has more kinetic energy while on the other hand, if a body moves on the medium and experience friction so it moves with little speed so we can say that the body has low kinetic energy.
An ambulance is traveling east at 62.4 m/s. Behind it a car travels along the same direction at 34.5 m/s. The ambulance driver hears his siren with a wavelength of 0.47 m. What wavelength would a stationary observer behind the ambulance measure for the sound? The velocity of sound in air is 343 m/s.
Answer:
The answer is "0.5555 m"
Explanation:
Where the reference leaves the list and the viewer is at rest:
[tex]\lambda'=\frac{v-v_s}{v} \times \lambda\\\\[/tex]
[tex]=\frac{343 \frac{m}{s} - (-62.4 \frac{m}{s})}{343 \frac{m}{s}} \times 0.47 \ m\\\\ =\frac{343 \frac{m}{s} + 62.4 \frac{m}{s}}{343 \frac{m}{s}} \times 0.47 \ m\\\\ =\frac{405.4 \frac{m}{s}}{343 \frac{m}{s}} \times 0.47 \ m\\\\ =\frac{405.4 \frac{m}{s}}{343 \frac{m}{s}} \times 0.47 \ m[/tex]
[tex]=0.5555 \ m[/tex]
