Answer: i think so this is correct
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Explanation:
Experiment of tossing a coin twice :
A.) Experimental outcome:
Head = H ; Tail = T ;
Head and Head = HH
Tail and Tail = TT
Head and Tail = HT
Tail and Head = TH
Number of head(s) on toss = z
C)
Experimental outcome ___number of heads(z)
HH _____________________2
TT _____________________ 0
TH _____________________ 1
HT _____________________ 1
D) the random variables defined are discrete because they are only take up integer values within a specified range
Which of the following explains how the role of government in health care policy would be influenced if the policy proposal in the passage were to be implemented?
Writing a Rule for a Translation
2 trapezoids are shown. Trapezoid 1 has points A (negative 7, 0), B (negative 5, 3), C (negative 1, 3), and D (negative 1, 0). Trapezoid 2 has points A prime (1, negative 3), B prime (3, 0), C prime (7, 0), and D prime (7, negative 3).
Which rule describes the translation?
(x, y) → (x – 8, y – 3)
(x, y) → (x – 3, y + 8)
(x, y) → (x + 8, y – 3)
(x, y) → (x + 3, y + 8)
Answer:
(x,y)-->(x+8,y-3)
Explanation:
I just took the test
1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The rate at which people leave the same movie theater is modeled by the function R defined by r(t) = 12eKo + 20. Both S (t) and r(t) are measured in people per hour and these functions are t valid for 10 < t < 22. At time t = 10, there are no people in the movie theater.(Problems are in the Picture and I need help)
Hi there!
a.
To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.
[tex]\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt[/tex]
Evaluate using a calculator:
[tex]= 899.97 \approx \boxed{900\text{ people}}[/tex]
b.
To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.
In other terms:
[tex]\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt[/tex]
We can evaluate using a calculator (math-9 on T1-84):
[tex]\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt[/tex]
[tex]= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}[/tex]
c.
If:
[tex]P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt[/tex]
Then:
[tex]\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)[/tex]
Evaluate at t = 20:
[tex]S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669[/tex]
[tex]S(20) - R(20) = 87.844 - 108.669 = -20.823[/tex]
This means that at t = 20, there is a NET DECREASE of people at the movie theater of around 20.823 (21) people per hour.
d.
To find the maximum, we must use the first-derivative test.
Set S(t) - R(t) equal to 0:
[tex]80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0[/tex]
Graph the function with a graphing calculator and set the function equal to y = 0:
According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.
Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.
Explain the key issue dividing Mugwumps, Halfbreeds, and Stalwarts.
This refers to the Gilded Age, first published in 1873 by Mark Twain.
The key issue dividing these three classes were mainly political.
The Mugwumps were members of the Republican party, who refused support to the nominee of 1884 and supported the Democratic candidate.
The Half-breed were rivals of the Stalwarts in the party control. They supported civil service reform and merit appointments to government posts while the Stalwarts favored the spoils system of political patronage. These were the result of a split in the Republican party.
