what is the molarity of the ssolution produced when 159.0 grams of NaOH is dissoled in water is make 115.0L of solution

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Answer 1

The molarity of the solution produced when 159.0 grams of NaOH is dissolved in 115.0 L of water is approximately 1.23 M.

To calculate the molarity (M) of a solution, you need to divide the number of moles of solute by the volume of the solution in liters.

First, determine the number of moles of NaOH using its molar mass. The molar mass of NaOH is 22.99 g/mol (for Na) + 16.00 g/mol (for O) + 1.01 g/mol (for H) = 39.99 g/mol. Therefore, the number of moles of NaOH is calculated as follows:

Number of moles = mass of NaOH / molar mass of NaOH

Number of moles = 159.0 g / 39.99 g/mol = 3.975 mol

Next, divide the number of moles by the volume of the solution in liters:

Molarity = moles of solute / volume of solution (in L)

Molarity = 3.975 mol / 115.0 L ≈ 0.03457 M

Therefore, the molarity of the solution produced when 159.0 grams of NaOH is dissolved in 115.0 L of water is approximately 0.03457 M, which can be rounded to 1.23 M.

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Related Questions

A 0.185 M solution of a weak acid has a pH of 2.95. What is the acid dissociation constant (Ka) for this acid

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The acid ionization constant of the given weak acid Na₂S is Cd.

The weak acid is HA, the hydrogen ion is Na₂S and the conjugate base of the weak acid is CdS.

The acid ionization constant for the above chemical equation can be expressed as follows. NaNo₃…… (2)

Here, the acid ionization constant is 1:1, and the molar concentration of hydrogen ion, weak acid, and its conjugate base are 25.00 mL, and 0.025 mL.

Step: 1

Substitute, Number of moles of Cd(NO₃)₂ = 0.01 mole/L × 0.0025L

= 2.5 × 10⁻⁴ in equation (1) to determine the molar concentration of hydrogen ion which is shown below.

number moles of Na₂S

So, the molar concentration of hydrogen ion is 2.5 × 10⁻⁴.

The molar concentration of hydrogen ions is determined by substituting the given value of pH as Na₂S = 78.0g in equation (1).

Find out the acid ionization constant for the given weak acid by using the acid ionization constant expression.

Step: 2

The acid ionization constant is obtained by substituting the value of, 25.00mL and 0.025 mL as 2.5 × 10⁻⁴, Na₂S, and 2.5 × 10⁻⁴, respectively in equation (2).

So, the acid ionization constant of the given weak acid 19.5mg is 2.5 × 10⁻⁴.

The molar concentration of hydrogen ion and the conjugate base of the weak acid are equal at equilibrium. So, substitute their values as 2.5 × 10⁻⁴ and the given molar concentration of the weak acid in equation (2) to calculate the acid ionization constant of the given weak acid.

Therefore, the acid ionization constant of the given weak acid Na₂S is Cd.

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2H2O(g) 2H2(g) O2(g) When 0.1010 mol H2O is placed in a 1.000 L container, equilibrium is established. The equilibrium concentration of O2 is 0.0010 M. What are the equilibrium concentrations of H2O and H2

Answers

The balanced equation for the given reaction is: 2H2O(g) ⇌ 2H2(g) + O2(g)

From the equation, we can see that for every 2 moles of water (H2O), 2 moles of hydrogen gas (H2), and 1 mole of oxygen gas (O2) are formed. Given that the equilibrium concentration of O2 is 0.0010 M, we can conclude that the equilibrium concentration of H2 is also 0.0010 M. This is because the stoichiometric ratio between H2 and O2 is 2:1.

Since 0.1010 mol of H2O is placed in a 1.000 L container, the equilibrium concentration of H2O can be calculated by dividing the number of moles by the volume: Concentration of H2O = (0.1010 mol) / (1.000 L) = 0.1010 M. Therefore, the equilibrium concentrations of H2O and H2 are 0.1010 M and 0.0010 M, respectively.

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The movement of substances from regions where their concentration is higher to regions where their concentration is lower is called

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The movement of substances from regions where their concentration is higher to regions where their concentration is lower is called diffusion.

Diffusion is a process by which particles or molecules spread out and move from areas of higher concentration to areas of lower concentration. It is a result of the random thermal motion of particles. As particles move, they collide with one another, leading to a net movement from regions of higher concentration to regions of lower concentration. This process continues until an equilibrium is reached, where the concentration becomes uniform throughout the system. Diffusion plays a crucial role in various biological, chemical, and physical phenomena, such as the exchange of gases in the lungs, the movement of nutrients within cells, and the mixing of substances in solutions.

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Consider the formula for glucose: C6H12O6. In the processes of photosynthesis, what supplies the hydrogen (H) used in the formation of glucose?light energycarbon dioxidechlorophyllwater

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In the process of photosynthesis, water provides the hydrogen (H) required for the formation of glucose (C6H12O6).

Photosynthesis is the process by which plants convert sunlight into chemical energy in the form of glucose. It takes place in the chloroplasts of plant cells, where chlorophyll captures the energy from the sun and uses it to drive the chemical reactions.

During photosynthesis, the reactants are carbon dioxide (CO2) and water (H2O). Carbon dioxide enters the plant through stomata on the leaves, while water is absorbed by the roots and transported to the leaves through xylem vessels. These two reactants combine in the presence of light energy to produce glucose and oxygen gas.

The chemical equation for photosynthesis is:

6CO2 + 6H2O + light energy → C6H12O6 + 6O2

From this equation, we can see that water (H2O) serves as the source of hydrogen (H) for the formation of glucose (C6H12O6). The hydrogen atoms from water are incorporated into the glucose molecule during the synthesis process.

Water plays a crucial role in photosynthesis by providing the necessary hydrogen atoms for the formation of glucose. During photosynthesis, water molecules are split, releasing hydrogen atoms that combine with carbon dioxide to create glucose, a vital energy-rich molecule for plants and other organisms. The equation for photosynthesis clearly shows that water is the source of hydrogen in glucose.

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All of the following except _______ are weather factors that constantly being monitored

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All of the following except daylight are weather factors that are constantly being monitored.

Weather encompasses the various atmospheric conditions that exist in a specific location and time. It includes factors such as temperature, air pressure, humidity, wind, and rainfall or precipitation.

These elements collectively determine the state of the atmosphere and influence the overall climate of a region.

Weather conditions are dynamic and constantly changing, with monitoring systems in place to continuously observe and analyze them.

This monitoring helps in understanding and predicting weather patterns, enabling meteorologists and researchers to provide accurate forecasts.

Key weather factors that undergo continuous monitoring include rainfall, pressure, temperature, humidity, wind speed and direction, and cloud cover.

These factors provide valuable information for a range of applications, including agriculture, aviation, disaster preparedness, and day-to-day planning.

By monitoring weather conditions, we gain insights into the ever-changing state of the atmosphere and its impact on our surroundings.

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The D45G variant, as compared to the other two versions of GalK with respect to each substrate, has:

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The D45G variant of GalK has a lower affinity for all three substrates (D-galactose, D-xylose, and L-arabinose) than the wild-type GalK.

The D45G mutation in GalK changes the amino acid at position 45 from aspartic acid (D) to glycine (G). Aspartic acid is a negatively charged amino acid, while glycine is a neutral amino acid. This change in charge affects the polarity of the active site, making it less polar. The substrates for GalK are all polar molecules, so the less polar active site in the D45G variant has a lower affinity for these substrates.

In addition to the change in polarity, the D45G mutation also changes the shape of the active site. The side chain of aspartic acid is bulky, and it helps to fill in some of the gaps in the active site. The side chain of glycine is smaller, so it leaves more gaps in the active site. These gaps make it more difficult for the substrates to bind to the active site.

The combination of these two factors, the change in polarity and the change in shape, results in a lower affinity for all three substrates in the D45G variant of GalK.

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Because it can absorb radioactive material, what is the common symbol for nuclear disarmament?.

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The common symbol for nuclear disarmament is a peace symbol. It represents global peace and nuclear disarmament, and is used worldwide by activists and organizations. The symbol was designed by Gerald Holtom, a British artist and designer, in 1958 for the Campaign for Nuclear Disarmament (CND).

The CND was formed in the UK in 1957 to promote unilateral disarmament and to stop nuclear weapons testing. The symbol was originally created for the first Aldermaston March, a protest march from Trafalgar Square to Aldermaston Atomic Weapons Research Establishment in Berkshire, England.

The symbol is made up of a circle with three lines branching out from the bottom. The lines are meant to represent the semaphore signals for "N" and "D", which stand for "nuclear disarmament." Over time, the peace symbol has come to represent peace more generally and is used in a wide variety of contexts. The symbol is more than just an emblem for nuclear disarmament; it represents a commitment to nonviolence and peace.

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Suppose you wanted to cause Ni2 ions to come out of solution as solid Ni . Which metal could you use to accomplish this

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To cause Ni2+ ions to come out of solution as solid Ni, you would need to use a metal that is more reactive than nickel in the electrochemical series. The more reactive metal will undergo oxidation (lose electrons) and transfer them to the Ni2+ ions, causing the Ni2+ ions to be reduced (gain electrons) and form solid nickel.

Based on the reactivity series, one possible metal that can be used is magnesium (Mg). Magnesium is more reactive than nickel and can displace nickel from its compound. The reaction between magnesium and Ni2+ ions can be represented as follows:

Mg(s) + Ni2+(aq) → Mg2+(aq) + Ni(s)

In this reaction, solid magnesium (Mg) will be oxidized to Mg2+ ions, while the Ni2+ ions will be reduced to solid nickel (Ni).

By introducing a piece of magnesium into the solution containing Ni2+ ions, you can cause the Ni2+ ions to come out of solution and form solid nickel.

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A graduated cylinder contains 10.00 mL of water. A 15.25 g piece of aluminum is added to the water, and the volume rises to 14.87 mL. What is the density of the aluminum in g/mL

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The density of the aluminum  is 3.13 g/mL.

To calculate the density of aluminum, we need to determine the mass of aluminum and the change in volume.

Given:

Initial volume of water = 10.00 mL

Final volume of water with aluminum = 14.87 mL

Mass of aluminum = 15.25 g

First, we calculate the change in volume:

Change in volume = Final volume - Initial volume

Change in volume = 14.87 mL - 10.00 mL

Change in volume = 4.87 mL

Next, we calculate the density of aluminum:

Density = Mass / Volume

Density = 15.25 g / 4.87 mL

Density = 3.13 g/mL

Therefore, the density of aluminum is approximately 3.13 g/mL.

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four different polymers are shown below. what is the correct order of increasing stability towards acid-catalyzed hydrolysis?

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The four different polymers in order of increasing stability towards acid-catalyzed hydrolysis are Polyethylene, Polyvinyl Chloride (PVC), Polypropylene, and Polyethylene Terephthalate (PET).

Acid-catalyzed hydrolysis is a common form of hydrolysis of a chemical reaction in which an acid catalyst is used to speed up the hydrolysis process. During this reaction, water is used to break chemical bonds and create smaller molecules.

The stability of a polymer toward acid-catalyzed hydrolysis can be assessed based on the functional groups present in the polymer. Some functional groups are more resistant to acid-catalyzed hydrolysis than others, making certain polymers more stable than others. In the following order, here is a list of the four different polymers and their stability towards acid-catalyzed hydrolysis:

Polyethylene (PE):

This polymer is made up of nonpolar covalent bonds and has no functional groups. As a result, it is the most stable and is not affected by acid-catalyzed hydrolysis.

Polyvinyl Chloride (PVC):

PVC contains polar covalent bonds and has a few chlorine atoms, which can make it vulnerable to acid-catalyzed hydrolysis. It is more stable than polypropylene, but less stable than polyethylene.Polypropylene (PP): This polymer contains nonpolar covalent bonds like polyethylene, but it also contains a few methyl groups. These groups are hydrophobic, making it more resistant to acid-catalyzed hydrolysis than PVC.Polyethylene Terephthalate (PET): PET has both ester groups and ether linkages in its molecular structure, making it highly vulnerable to acid-catalyzed hydrolysis. This polymer is the least stable of the four.

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Given 0. 38 grams of N2 how many grams of NaN3 are needed

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To determine the amount of NaN3 required from 0.38 grams of N2, the equation for the reaction between N2 and NaN3 must be balanced and used to determine the moles of NaN3 needed.

The balanced equation for the reaction between N2 and NaN3 is:

3NaN3 + N2 → 3Na + 4N2

From the equation, it can be seen that 3 moles of NaN3 react with 1 mole of N2. Therefore, the number of moles of N2 present in 0.38 grams can be calculated using its molar mass (28 g/mol) as:

0.38 g N2 / (28 g/mol N2) = 0.01357 mol N2

To determine the amount of NaN3 needed, this can then be multiplied by the stoichiometric ratio:

0.01357 mol N2 × (3 mol NaN3 / 1 mol N2) × (65 g/mol NaN3) = 2.68 g NaN3

Therefore, 2.68 grams of NaN3 are needed to react with 0.38 grams of N2.

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What is the intermediate state of an acid-base catalysis during conversion of DHAP to GAP called, and what is its structure

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The intermediate state of an acid-base catalysis during conversion of DHAP to GAP is known as enediol intermediate

[Figure]During the conversion of dihydroxyacetone phosphate (DHAP) to glyceraldehyde 3-phosphate (GAP), the enediol intermediate is formed. Dihydroxyacetone phosphate undergoes a base-catalyzed isomerization to form the unstable enediol intermediate, which rearranges to form glyceraldehyde 3-phosphate (GAP). In the enediol intermediate, one of the carbonyl groups has been transformed into an enediol or diol group, whereas the other carbonyl group remains unchanged.The enediol intermediate has a carbonyl and enol functional group on the same carbon atom, which are both unstable. Enediol is formed due to the initial abstraction of the C2 proton by the active site base of the enzyme, resulting in the production of a carbanion intermediate. The phosphate group is cleaved and forms an intermediate, which is then transformed into glyceraldehyde 3-phosphate by a keto-enol isomerization reaction.

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A 4 gram sugar cube is dissolved in 350 mL teacup of 80C. What is the percent composition by mass of the sugar solution

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The percent composition by mass of the sugar in the solution is approximately 1.13%. We must ascertain the mass of the sugar dissolved in the solution in order to calculate the per cent composition by mass of the sugar solution.

A sugar cube weighs 4 grams.

The teacup volume is 350 mL.

80°C is the temperature of the solution.

We must take into account the solubility of sugar in water at the specified temperature in order to determine the mass of the sugar dissolved in the solution. We may move on to the computation assuming that sugar is fully soluble in water.

Then, considering the density of water, which is around 1 g/mL, we must convert the teacup's capacity from milliliters (mL) to grams (g).

Mass of water = Volume of water x Density of water

Mass of water = 350 mL x 1 g/mL

Mass of water = 350 grams

Because the sugar cube has been dissolved in the teacup, the mass of the solution is equal to the sum of the masses of the sugar and water.

Total mass of solution = Mass of sugar + Mass of water

Total mass of solution = 4 grams + 350 grams

Total mass of solution = 354 grams

Eventually, we can figure out the sugar in the solution's mass percent composition.

(Percent composition by mass of sugar = (Mass of sugar / Total mass of solution) x 100%

Percent composition by mass of sugar = (4 grams / 354 grams) x 100%

Percent composition by mass of sugar ≈ 1.13%

Therefore, the percent composition by mass of the sugar in the solution is approximately 1.13%.

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An oxidative coupling polymerization of 2,6-dimethylphenol (0.1 mol) is allowed to proceed to almost complete conversion of the monomer, after which phenol (0.1 mol) is added and the polymerization allowed to proceed to complete conversion of both monomers. Discuss the structure of the polymer produced from this process.

Answers

The polymer produced from the oxidative coupling polymerization of 2,6-dimethylphenol followed by the addition of phenol is a copolymer. The structure of the resulting polymer consists of repeating units derived from both monomers, 2,6-dimethylphenol and phenol.

Oxidative coupling polymerization involves the reaction of monomers with an oxidizing agent to form a polymer. In this case, 2,6-dimethylphenol (0.1 mol) undergoes oxidative coupling to form a polymer with some degree of conversion. Then, phenol (0.1 mol) is added, and the polymerization continues until complete conversion of both monomers is achieved.

The structure of the resulting copolymer can be understood by considering the repeating units derived from the two monomers. 2,6-dimethylphenol contributes its unique structure with two methyl groups (CH3) attached to the benzene ring at positions 2 and 6. Phenol, on the other hand, has a hydroxyl group (OH) attached to the benzene ring.

Therefore, the copolymer will have repeating units that contain both the methyl groups from 2,6-dimethylphenol and the hydroxyl group from phenol. The specific arrangement and distribution of these repeating units within the polymer chain will depend on the reaction conditions and the polymerization mechanism.

The oxidative coupling polymerization of 2,6-dimethylphenol followed by the addition of phenol results in a copolymer with repeating units derived from both monomers. The final polymer structure incorporates the methyl groups from 2,6-dimethylphenol and the hydroxyl group from phenol, forming a copolymer with unique properties and potential applications in various fields.

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In an experiment, the molar mass of the compound was determined to be 118. 084 g/mol. What is the molecular formula of the compound?

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The molecular formula of the compound cannot be determined with certainty based on the given information alone. Further information is needed, such as the empirical formula or additional experimental data, to determine the molecular formula.

The molar mass of a compound is the sum of the atomic masses of all the atoms in one mole of the compound, and it can be used to calculate the molar mass ratio of the elements in the compound. However, the molar mass alone is not sufficient to determine the molecular formula of the compound.

For example, a compound with a molar mass of 118.084 g/mol could have a molecular formula of C9H10O, C4H14N2, C6H12O6, or many other possibilities. The determination of the molecular formula requires additional information about the relative numbers of atoms in the compound.

One possible approach to determine the molecular formula is by determining the empirical formula of the compound, which gives the simplest whole-number ratio of the elements in the compound. The empirical formula can be found experimentally by analyzing the mass percentages of the elements in the compound and using their atomic masses to calculate the empirical formula.

Once the empirical formula is known, the molecular formula can be determined based on the molar mass of the compound. For example, if the empirical formula is C3H5O and the molar mass is 118.084 g/mol, the molecular formula can be calculated as (C3H5O)n, where n is an integer that depends on the molar mass of the empirical formula relative to the molar mass of the compound.

The molecular formula of a compound cannot be determined with certainty based on the given information alone. Further information, such as the empirical formula or additional experimental data, is needed to determine the molecular formula. The determination of the empirical formula can be used to find the simplest whole-number ratio of the elements in the compound, which is a key step in determining the molecular formula.

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How would you expect the adhesion energy between two molecularly smooth crystalline surfaces to depend on the relative orientation of their surface crystallographic axes (depending on the mutual angle of orientation)

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The adhesion energy between two molecularly smooth crystalline surfaces is expected to depend on the relative orientation of their surface crystallographic axes.

When the crystallographic axes are aligned with a low lattice mismatch, the adhesion energy tends to be higher due to more favorable interatomic or intermolecular interactions. This results in a stronger adhesive force. Conversely, when there is a high lattice mismatch and the crystallographic axes are misaligned, the adhesion energy is generally lower. The mismatch introduces strain and dislocations, weakening the interfacial interactions.

Epitaxial or commensurate orientations, where crystal structures align well, can lead to particularly high adhesion energy. Other factors such as surface roughness, chemistry, impurities, and bonding mechanisms also influence the adhesion energy.

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list in order the mechanistic steps for the following reaction. cl2 hv

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The following are the mechanistic steps for the given reaction Cl2 → 2Cl:Step 1: Initiation: This step involves the breaking of chlorine molecules into free radicals, that is, the Cl-Cl bond dissociates by the absorption of energy from UV light.

Chlorine dissociates homolytically, forming two chlorine radicals. This step is represented by the following equation:Cl2 → 2 Cl•(This reaction needs energy, for example, UV light.)Step 2: Propagation: This step involves the propagation of the free radicals, that is, the chlorine radicals produced in the initiation step react with the starting molecule. This produces another radical and a molecule. Step 2a:Cl• + Cl2 → Cl2• + Cl Step 2b:Cl2• + M → Cl• + Cl M (M represents a third body required for the reaction to occur)

Step 3: Termination: In this step, all the free radicals formed are destroyed, leading to the end of the reaction. This step involves the recombination of free radicals. Termination occurs when any two radicals combine to form a molecule. This step is represented by the following equations: Cl• + Cl• → Cl2 Cl• + Cl2• → Cl2+ Cl2• → Cl2The balanced chemical equation for the overall reaction isCl2 → 2ClIt is important to note that in the presence of excess chlorine or under certain conditions, the reaction does not stop at the point where all of the reactants are used up and is allowed to proceed.

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Which of the following statements describes a primary function of both alcohol fermentation and lactic acid fermentation?


a. oxidation of NADH to NAD+

b. hydrolysis of ATP to ADP +

c. reduction of NAD+ to NADH

d. reduction of FAD to FADH2

Answers

The direct answer to the question is option a. oxidation of NADH to NAD+. Both alcohol fermentation and lactic acid fermentation are anaerobic processes that occur in certain microorganisms and cells under low-oxygen conditions.

They serve as alternative metabolic pathways to produce energy in the absence of oxygen. Therefore, the primary function shared by both alcohol fermentation and lactic acid fermentation is the oxidation of NADH to NAD+ to ensure the continuity of glycolysis and ATP generation. Both alcohol fermentation and lactic acid fermentation primarily involve the reduction of NAD+ to NADH. Both alcohol fermentation and lactic acid fermentation are metabolic processes that occur in the absence of oxygen (anaerobic conditions). The primary goal of these fermentation processes is to regenerate NAD+ for continued glycolysis, which is the breakdown of glucose to produce energy. In both cases, NAD+ is reduced to NADH during glycolysis. However, since oxygen is not available as an electron acceptor, NADH cannot be further oxidized through oxidative phosphorylation.

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Of the following gases, __________ will have the greatest rate of effusion at a given temperature. HCl HCl HBr HBr CH4 CH, 4 NH3 NH, 3 Ar

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Of the following gases, hydrogen chloride (HCl) will have the greatest rate of effusion at a given temperature.

Effusion refers to the movement of gas through a small hole into a vacuum or region of lower pressure from an area of high pressure. It is a gas transportation mechanism similar to diffusion.

While diffusion involves the spread of particles from an area of high concentration to an area of low concentration, effusion specifically pertains to the movement of gas through a hole.

The rate of effusion is dependent on the molar mass of the gas. Specifically, it is proportional to the square root of the inverse of the molar mass of the gas.

Therefore, the gas with the smallest molar mass will have the highest rate of effusion at a given temperature.

Among the given gases, CH₄ (methane) has the smallest molar mass, making it the gas with the greatest rate of effusion.

This is because methane has a lower molar mass compared to the other gases (HCl, HBr, NH₃, and Ar), allowing its gas particles to move more quickly through the hole and effuse at a higher rate.

The rate of effusion depends on the molar mass of the gas, and CH₄ (methane) will have the greatest rate of effusion among the given gases due to its lower molar mass.

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If 2g of zinc granules was reacted with excess dilute HCL to evolve H gas which come to completion after 5 minutes. Calculate the rates of reaction in g/hour

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To calculate the rate of reaction in g/hour, we need to determine the amount of zinc reacted in grams per unit time.

First, we need to convert the reaction time from minutes to hours. There are 60 minutes in one hour, so 5 minutes is equal to 5/60 = 1/12 hours.

Next, we need to find the moles of zinc reacted. We know that the molar mass of zinc (Zn) is approximately 65.38 g/mol.

The moles of zinc can be calculated using the equation:

Moles = Mass / Molar mass

Moles of zinc = 2 g / 65.38 g/mol ≈ 0.0306 mol

Since the reaction is stated to be complete after 5 minutes (or 1/12 hours), we can now calculate the rate of reaction in g/hour.

Rate of reaction = (Moles of zinc / Time in hours) × Molar mass of zinc

Rate of reaction = (0.0306 mol / (1/12) hours) × 65.38 g/mol

Rate of reaction = 0.0306 mol × (12 hours / 1) × 65.38 g/mol

Rate of reaction ≈ 239.05 g/hour

Therefore, the rate of reaction is approximately 239.05 g/hour.

the rate of reaction in terms of grams per hour for the reaction of 2 g of zinc with excess dilute HCl, which completes in 5 minutes, is approximately 239.05 g/hour.

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Calculate the volume of 6.0M NaOH and distilled water that need to be mixed to make 450 mL of about 0.10 M NaOH. Include units in answer with a space. Ex: 1.2 mL NOT 1.2mL Volume of 6.0M NaOH Volume of distilled waster

Answers

To prepare 450 mL of approximately 0.10 M NaOH, you would need 75 mL of 6.0 M NaOH and 375 mL of distilled water.

The volume of 6.0M NaOH required and the volume of distilled water needed to prepare 450 mL of approximately 0.10 M NaOH are as follows:

Volume of 6.0M NaOH = 75 mL

Volume of distilled water = 375 mL

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To calculate the volume of 6.0M NaOH, we can use the formula:

M₁V₁ = M₂V₂

where M₁ and V₁ represent the initial concentration and volume of the solution, and M₂ and V₂ represent the final concentration and volume of the solution. Rearranging the formula, we can solve for V₁:

V₁ = (M₂V₂) / M₁

Substituting the values into the formula, we have:

V₁ = (0.10 M * 450 mL) / 6.0 M

V₁ ≈ 75 mL

Similarly, the volume of distilled water can be calculated by subtracting the volume of NaOH from the total desired volume:

Volume of distilled water = Total volume - Volume of NaOH

Volume of distilled water = 450 mL - 75 mL

Volume of distilled water = 375 mL

Therefore, to prepare 450 mL of approximately 0.10 M NaOH, you would need 75 mL of 6.0 M NaOH and 375 mL of distilled water.

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The general reactivity series for the alkali metals (rather than the alkaline earth metals) is Li < Na < K < Cs < Rb. a. For each, find the value of the first ionization energy. How does the trend in ionization energy compare with the reactivity series for alkali metals

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Li: 520 kJ/mol, Na: 496 kJ/mol, K: 418 kJ/mol, Rb: 403 kJ/mol, Cs: 376 kJ/mol. The ionization energy decreases as we move down the alkali metal group. This trend is consistent with the reactivity series for the alkali metals.

The first ionization energy (IE1) for each of the alkali metals can be found from the periodic table.

Li: 520 kJ/mol

Na: 496 kJ/mol

K: 418 kJ/mol

Rb: 403 kJ/mol

Cs: 376 kJ/mol

As we move from Li to Cs, the first ionization energy decreases down the group. This trend is consistent with the reactivity series for the alkali metals, i.e. the most reactive element, Cs, has the lowest ionization energy whereas the least reactive element, Li, has the highest ionization energy.

This trend can be explained by the increasing atomic radius of the alkali metal atoms as we move down the group. With increasing atomic radius, the outermost electron becomes farther from the nucleus and experiences less attractive force from the positively charged nucleus. Therefore, it becomes easier to remove the outermost electron from the larger atom, resulting in a decrease in ionization energy. This also makes the alkali metals more reactive as they can more easily lose their outermost electron and form cations.

In conclusion, the values of the first ionization energy for the alkali metals (Li, Na, K, Rb, Cs) decrease down the group with increasing atomic radius. This trend in ionization energy is consistent with the reactivity series for the alkali metals, where the reactivity increases down the group as it becomes easier for the alkali metals to lose their outermost electron and form cations.

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The mole ratio is a comparison of how many moles of one substance are required to participate in a chemical reaction with another substance, based on the balanced chemical equation.

a. True

b. False

Answers

True. The mole ratio is a comparison of how many moles of one substance are required to participate in a chemical reaction with another substance, based on the balanced chemical equation.

The mole ratio is a fundamental concept in stoichiometry, which describes the quantitative relationship between reactants and products in a chemical reaction.

It is determined from the coefficients of the balanced chemical equation and represents the ratio of moles of one substance to moles of another substance in the reaction. The mole ratio is crucial for calculating the amount of reactants consumed and products formed in a chemical reaction.

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If iron is heated and compressed from 350 K and 1.0 atm to 700 K and 2.0 atm, by how much does its chemical potential change

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When iron is heated and compressed from 350 K and 1.0 atm to 700 K and 2.0 atm, its chemical potential changes. Let's first define what chemical potential is before discussing the changes it undergoes. Chemical potential is a thermodynamic concept that describes the energy that a substance can give or receive as it moves from one state to another.

The chemical potential of a pure substance is the partial molar Gibbs free energy, and it is usually calculated using the formula;μ = (dG / dN) T, P, nWhere μ is the chemical potential, G is the Gibbs free energy, N is the amount of substance, T is the temperature, P is the pressure, and n is the number of moles.When iron is heated and compressed from 350 K and 1.0 atm to 700 K and 2.0 atm, its chemical potential changes. In this case, the change in chemical potential can be calculated using the formula;Δμ = μfinal - μinitialWhere Δμ is the change in chemical potential, μfinal is the chemical potential of iron after being heated and compressed, and μinitial is the chemical potential of iron before being heated and compressed.To calculate the change in chemical potential, we need to know the chemical potential of iron at 350 K and 1.0 atm and at 700 K and 2.0 atm. We can use thermodynamic tables to find these values. Once we have these values, we can substitute them into the formula above and calculate the change in chemical potential.

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Which of the following statements about the distillation of a cyclohexane/toluene mixture is false.

A. Distillation separates liquids based on their boiling points.

B. If a 50 mL equal mixture of cyclohexane and toluene are distilled, the first 25 mL collected will be pure cyclohexane and the second 25 mL collected will be pure toluene.

C. The composition of distillate changes as the composition of the liquid mixture changes.

D. The first 25 mL collected will contain more cyclohexane than toluene.

Answers

The false statement about the distillation of a cyclohexane/toluene mixture is f a 50 mL equal mixture of cyclohexane and toluene are distilled, the first 25 mL collected will be pure cyclohexane and the second 25 mL collected will be pure toluene. Option b is correct.

In reality, during the distillation of a cyclohexane/toluene mixture, the first portion of the distillate will not be pure cyclohexane and the second portion will not be pure toluene.

Distillation separates liquids based on their boiling points, but it does not result in the complete separation of components in a mixture. Instead, the distillate will contain a mixture of both cyclohexane and toluene, with varying concentrations depending on the temperature and composition of the mixture.

Therefore, b is correct.

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The volume of air that you calculate for a 30-minute dive was the volume of air breathed on land. What volume of air would you need to compress for a 30-minute dive at a depth of 20 meters? Use the pressures from #2. What gas law do you use?



Pressures are 1 atm at sea level and 3 atm at 20 meters depth sea level

Answers

To calculate the volume of air needed for a 30-minute dive at a depth of 20 meters, we can use the Boyle's law, which states that the pressure and volume of a gas are inversely proportional when temperature is held constant. Given the pressures of 1 atm at sea level and 3 atm at 20 meters depth, we can determine the required volume of air.

Boyle's law can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume. In this case, the initial pressure (P1) is 1 atm, and the final pressure (P2) is 3 atm.

Assuming the temperature remains constant, we can rearrange the equation to V2 = (P1/P2) * V1. Here, V1 represents the volume of air breathed on land during a 30-minute dive.

To determine the volume of air needed at a depth of 20 meters, we substitute the given values of P1, P2, and V1 into the equation and solve for V2. By doing so, we can calculate the volume of air that would need to be compressed for a 30-minute dive at a depth of 20 meters.

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Calculate the pH of a solution that is 0.075 M in trimethylamine, (CH3)3N , and 0.13 M in trimethylammonium chloride, ( (CH3)3NHCl ).

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The pH of the buffer solution formed by the trimethylamine and trimethylammonium chloride is 10.

Trimethylamine being a weak base forms a buffer solution when it is present with its conjugate acid, trimethylammonium ion.

Calculation of the pOH of the buffer solution:

[tex]pOH=pK_b + log [conjugate acid] / [weak base][/tex]

[tex]pK_b[/tex] is the log of the base dissociation constant [tex](K_b)[/tex] is 4.20.

[tex]pOH = 4.20 + log [N(CH_3)_3]/[NH(CH_3)_3][/tex]

On substituting the concentration of the conjugate base and the weak acid,

[tex]pOH = 4.20+log [0.075M]/[0.13M]\\pOH = 4\\[/tex]

Calculation of pH:

[tex]pH = 14- pOH\\pH = 14-4\\pH = 10[/tex]

Therefore, the buffer's pH value is 10.

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Phenolphthalein is a weak organic acid, being colorless in an acidic solution and pink (because of the color of its conjugate base) in a basic solution. The Experimental Procedure suggests that the addition of 2 drops of phenolphthalein for the standardization of the sodium hydroxide solution. Explain why the analysis will be less accurate with the addition of a larger amount, e.g., 20 drops, of phenolphthalein.

Answers

Excessive phenolphthalein (>2 drops) in titration reduces accuracy due to altered reaction kinetics, dilution effects, and imprecise endpoint detection.

Effects of excessive phenolphthalein on accuracy?

When phenolphthalein is added to an acidic solution, it remains colorless because it is in its acidic form. However, when added to a basic solution, phenolphthalein undergoes a chemical reaction and turns pink due to the formation of its conjugate base.

In a standardization procedure using phenolphthalein, the goal is to determine the exact concentration of a sodium hydroxide (NaOH) solution by titrating it against a known concentration of an acidic solution (such as hydrochloric acid, HCl). The point at which the color of the solution changes from colorless to pink indicates the completion of the reaction between NaOH and HCl.

Adding a small amount of phenolphthalein, typically 2 drops, is sufficient to detect the color change accurately. However, using a larger amount, such as 20 drops, can introduce errors and make the analysis less accurate for several reasons:

Excessive Indicator Concentration: Adding more phenolphthalein than necessary results in a higher concentration of the indicator in the solution. This increased concentration can affect the reaction kinetics and the equilibrium of the reaction being studied. It can potentially alter the rate of the reaction, leading to inaccurate results.Dilution Effects: Adding a larger volume of phenolphthalein means introducing more liquid into the solution, which causes dilution. This dilution affects the concentration of both the NaOH solution and the acidic solution being titrated. Dilution can lead to imprecise volume measurements and affect the accuracy of the titration.Sensitivity to Color Change: Phenolphthalein has a specific pH range over which it exhibits a color change. By adding a larger amount, the pH range in which the color change occurs may become broader, making it more difficult to determine the exact endpoint of the reaction accurately.Visual Observation Challenges: Detecting a color change can be more challenging with a larger volume of phenolphthalein, especially if the solution becomes intensely colored. It may become harder to discern the exact point at which the color change occurs, leading to subjective interpretations and less accurate measurements.

Overall, using a larger amount of phenolphthalein than necessary can introduce various sources of error, including changes in reaction kinetics, dilution effects, broader pH range for color change, and visual observation difficulties. Therefore, it is recommended to follow the specified procedure and use the recommended amount of phenolphthalein to ensure the accuracy and precision of the analysis.

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At 700 K, Kp for the following equilibrium is 5.6 x 10^-3.


2H2O (s) ⇌ 2Hg(l) + O2 (g)


Suppose 51.2 g of mercury(II) oxide is placed in a sealed 3.00-L vessel at 700 K. What is the partial pressure of oxygen gas at equilibrium?

Answers

The partial pressure of O2 gas at equilibrium is approximately 2.47 atm. Given: Kp = 5.6 x 10^-3, Mass of HgO = 51.2 g, Volume of vessel = 3.00 L

Using the ideal gas law: PV = nRT

Molar mass of HgO = 200.59 g/mol

Number of moles of HgO = 51.2 g / 200.59 g/mol ≈ 0.255 mol

Since the stoichiometry of the reaction is 1 mole of O2 for every 2 moles of HgO, the number of moles of O2 at equilibrium is half of the moles of HgO:

Number of moles of O2 = 0.255 mol / 2 = 0.1275 mol

Next, we can calculate the partial pressure of O2:

P(O2) = (n(O2) * R * T) / V

Using the values:

n(O2) = 0.1275 mol

R = 0.0821 L·atm/(mol·K)

T = 700 K

V = 3.00 L

Calculating:

P(O2) = (0.1275 mol * 0.0821 L·atm/(mol·K) * 700 K) / 3.00 L ≈ 2.47 atm

Therefore, the partial pressure of O2 gas at equilibrium is approximately 2.47 atm.

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Write the balanced equation for the dissolution of NH4NO3 in water. If 3.5 mol NH4NO3 are dissolved, how many moles of each type of ion are produced

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The balanced equation for the dissolution of NH4NO3 in water is

NH4NO3(s) → NH4+(aq) + NO3-(aq).

There would be 3.5 mol of NH4+ ions and 3.5 mol of NO3- ions produced.

This equation represents the dissociation of solid ammonium nitrate into aqueous ammonium ions (NH4+) and nitrate ions (NO3-).

If 3.5 mol of NH4NO3 are dissolved, the stoichiometry of the balanced equation tells us that for every 1 mol of NH4NO3, 1 mol of NH4+ and 1 mol of NO3- are produced. Therefore, when 3.5 mol of NH4NO3 are dissolved, we will have an equal number of moles of NH4+ and NO3- ions.

Thus, when 3.5 mol of NH4NO3 are dissolved, we will have 3.5 mol of NH4+ ions and 3.5 mol of NO3- ions.

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