Answer:
F = 159.07 N
Explanation:
Given that,
Mass of a tennis ball, m = 54.9 g = 0.0549 kg
It accelerates from rest to a speed of 45.1 m/s.
The impact with the racket gives the ball a constant acceleration over a distance of 35.1 cm = 0.351 m
We need to find the magnitude of net force acting on the ball.
Let a be the acceleration of the ball. Using third equation of motion to find it.
[tex]v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(45.1)^2-(0)^2}{2\times 0.351}\\\\=2897.45\ m/s^2[/tex]
Net force,
F = ma
F = 0.0549 kg × 2897.45 m/s²
= 159.07 N
Hence, the net force acting on the ball is 159.07 N.
who is the best soccer player?
A bullet of mass 4.0g is fired from a rifle of mass 2.0kg with muzzle velocity of 380m/s. What is the initial recoil velocity of the rifle?
Answer:
v = 0.76 [m/s]
Explanation:
The linear momentum generated by the shot must be calculated. This can be calculated using the following expression.
[tex]P=m*v\\[/tex]
where:
P = linear momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
[tex]P=0.004*380\\P=1.52[kg*m/s][/tex]
Now we can calculate the recoil velocity, because the momentum is equal for the rifle.
[tex]P=m*v\\v = P/m\\v = 1.52/2\\v = 0.76[m/s][/tex]
If an object accelerates from rest, with a constant of 8 m/s2, what will its velocity be after 35s?
Answer:
Its speed will be 280 m/s
Explanation:
Constant Acceleration Motion
It's a type of motion in which the speed of an object changes by an equal amount in every equal period of time.
If a is the constant acceleration, vo the initial speed, vf the final speed, and t the time, vf can be calculated as:
[tex]v_f=v_o+at[/tex]
The object accelerates from rest (vo=0) at a constant acceleration of [tex]a=8\ m/s^2[/tex]. The final speed at t=35 seconds is:
[tex]v_f=0+8*35[/tex]
[tex]v_f=280\ m/s[/tex]
Its speed will be 280 m/s
what is the speed of a 330kg beam dropped from 40m
Answer:
28 m/s
Explanation:
We can use this constant acceleration kinematic equation to find the speed of this beam as it is dropped from 40 m.
Since the object is dropped vertically downwards, we know that the object is in free-fall.
The acceleration of this object is -g, which is -9.8 m/s² since we are making the positive direction upwards and the negative direction downwards.
The initial velocity is 0 m/s since the object is dropped and starts from rest.
The final velocity is what we are trying to solve for.
The displacement in the y-direction is 40 m.
Now we can see which equation contains these 4 variables:
v² = v₀² + 2aΔxPlug in the known variables.
v² = (0)² + 2(-9.8)(-40)Simplify this equation.
v² = 784Take the square root of both sides.
v = 28 m/sThe speed of the 330 kg beam dropped from 40 m is 28 m/s.
Answer:
28 m/sExplanation:
Given information :
mass = 330kg
height =40m
v = √2gh
Where ;
g = acceleration due to gravity = 9.8 or 10 m/s
h = height
how much total energy of the beam just as it hits the ground =
mgh
[tex]330\times 10\times 40\\\\\\=132000[/tex]
Speed at which the beam will hit the ground :
[tex]v = \sqrt{2\times 10\times40} \\\\=\sqrt{800}\\\\=20\sqrt{2}\\\\v=28.28427[/tex]
how is this please help me
Answer:
jsjsjsjsmkskskskksksks
1) Think of planting a tree. You dig the hole, put it in, and fill it back in. Next,
you need to attach 3 ropes to the tree to try to keep it straight while it grows.
You put the ropes on it like a "V". Where do you have to put the third rope to
ensure your tree is straight?
Answer:
at the top of the tree I hope it will help you please follow me
a golf ball has a mass 0.046 kkg rests on a tee it is struck by a golf club with an effectiv mass of 0.22 and speed of 44 assuming the collision is elastic, find the speed of the ball when it leaves the tee
Answer:
210 m/s
Explanation:
We will use this equation for an elastic collision:
m₁v₁ + m₂v₂ = m₁v₁ + m₂v₂ The left side of the equation is before the collision; the right side is after the collision.In this case, m₁ = mass of golf ball (0.046 kg) and m₂ = mass of the golf club (0.22 kg).
Left side of equation:v₁ is 0 m/s since the ball is at rest on the tee.
v₂ is 44 m/s, given in the problem.
Right side of equation:v₁ is what we are trying to find.
v₂ is 0 m/s since the ball will be at rest on the ground.
⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯Plug these values into the elastic collision equation:
(0.046 kg)(0 m/s) + (0.22 kg)(44 m/s) = (0.046 kg)(v₁) + (0.22 kg)(0 m/s)Simplify this equation.
(0.22 kg)(44 m/s) = (0.046 kg)(v₁)Get rid of the units.
(0.22)(44) = 0.046v₁Multiply the left side of the equation.
9.68 = 0.046v₁Divide both sides by 0.046.
210.434782609 = v₁ 210 m/s = v₁The speed of the ball when it leaves the tee is about 210 m/s.
It is not possible to accurately calculate instantaneous velocity.
TRUE
FALSE
Which of Earth's Layers is solid but still "bendable"?
Answer:
Mantlee
Explanation:
HELP PLEASE NOW!!!!!!
A car slows down from -27.7m/s to -10.9m/s while undergoing a displacment of -105m. What was its acceleration?
Given :
A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m.
To Find :
The acceleration of the car.
Solution :
We know, by equation of motion :
[tex]2as = v^2 -u^2\\\\a = \dfrac{v^2 -u^2 }{2s}\\\\a = \dfrac{(-10.9)^2 - ( -27.7)^2}{2\times ( -105 )}\\\\a = 3.088\ m/s^2[/tex]
Therefore, acceleration of the car is 3.088 m/s².
the great pyramid of khufu (giza, egypt) is about 140m tall. How much work would be required to raise an average - sized pyramid black (2.5 tons) to this height?
some sedimentary rocks are made from smaller rounded stones that have been cemented together called what?
A: Intrusive rock
B: conglomerate rock
C: extrusive rock
D: marble
Answer:
B.
Explanation:
Intrusive and extrusive rocks are igneous rocks and marble is metamorphic, by the process of elimination, B would be the correct answer.
Answer:
answer is B
Explanation:
7. What force is required to accelerate a 100 kg car to 4 m/s27 F=ma
O A. 25N
B. 104N
C. 400N
Answer:
is the formula is F=MA so
F=100kg×4m/s=400n
so the answer is 400n
The vocal cords in your throat _____________.
collapse
vibrate
compress
Answer:
vibrate
Explanation:
Vocal folds vibrate when excited by aerodynamic phenomena; they are not plucked like a guitar string. Air pressure from the lungs controls the open phase. The passing air column creates a trailing “Bernoulli effect,” which controls the close phase.
hope it helps!!
A balloon drifts 14 km at an angle of 30º to the ground. What is the vertical component of the balloon
Sin is the vertical component. So multiply sin 30 and 14. BOOM! You got the answer.
[tex] \sin(30) \times 14 \: = 7[/tex]
Electricity costs 10p per unit. How much will it cost Sam to use a 85W laptop and a 60W lamp for an hour?
It will cost Sam "1.45 p. per hr" to use an 85W laptop and a 60W lamp. To understand the calculation, check below.
Power and ElectricityAccording to the question,
Electricity cost = 10 p per unit
Laptop power = 85 W
Lamp power = 60 W
We know the standard unit, KW/hr = 1000 W/hr
then,
= 85 + 60
= 145 W
By fractioning,
= [tex]\frac{145}{1000}[/tex]
= 0.145 KWH
hence,
The cost will be:
= 0.145 × 10 p
= 1.45 p. per hr
Thus the above approach is correct.
Find out more information about electricity here:
https://brainly.com/question/11517288
The type of charge on an object depends on what? Material of object quality of object force of rubbing thickness of object please tell
Explanation:
Type of charge on an object depends upon the material of the object. However, most of the material are electrically neutral. Since, they have equal number of positive and negative charges on them. So, they act as if they have no charge at all.
Hence, option A is correct.
A car accelerates at a rate of 2.0 m/s2. If its original speed is 8.0 m/s, how many seconds will it take the car to reach a final speed of 28.0 m/s?
Answer:
[tex]\huge\boxed{\sf Time = 10 \ seconds}[/tex]
Explanation:
Given:
Initial Velocity = [tex]\sf V_{i}[/tex] = 8.0 m/s
Final Speed = [tex]\sf V_{f}[/tex] = 28.0 m/s
Acceleration = a = ?
Required:
Time = t = ?
Formula:
[tex]\sf a = \frac{V_{f} - V_{i}}{t}[/tex]
Solution:
[tex]\sf 2 = \frac{28-8}{t} \\\\2 = \frac{20}{t} \\\\t = \frac{20}{2} \\\\t = 10 \ seconds\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807a projectile is fixed from ground level with a velocity 500m/s at 30 degree to the horizontal .find its horizontal range, the greatest height and time to reach the greatest height.
Answer:
1. 22092.31 m
2. 3188.78 m
3. 25.51 s
Explanation:
Let's split this projectile's motion into its horizontal and vertical components:
Horizontal (v_x) component: 500 * cos(30)Vertical (v_y) component: 500 * sin(30)Since this projectile is in constant acceleration (9.8 m/s² vertically downwards and 0 m/s² horizontally), we can use the kinematic equations for constant acceleration.
Let's find the time it takes for the projectile to reach its greatest height first by using our knowledge that, at the top of its trajectory, the projectile will have a final velocity of 0 m/s before changing its direction and falling down.
Therefore, we can use the equation that contains the variables a_y, v_f, v_i, and t in order to solve for time t.
This equation is: v = v_0 + at, where v is the final velocity, v_0 is the vertical component of the initial velocity, a is the acceleration in the y-direction, and t is the time of flight of the projectile.
Plug known values into the equation:
0 = 500 * sin(30) + (-9.8)tSubtract 500 * sin(30) from both sides of the equation.
-500 * sin(30) = -9.8tDivide both sides by -9.8.
t = 25.51The time it takes the projectile to reach its greatest height is 25.51 seconds.
Now we can use this time t to find the greatest height of the object, which will be the displacement in the y-direction at t = 25.51 seconds.
We can use this equation that contains the variables displacement (Δx), initial velocity (v_0), acceleration (a_y), and time (t):
Δx = v_0 t + 1/2at²Plug known values into the equation.
Δx = [500 * sin(30)] * 25.51 + 1/2(-9.8)(25.51)² Δx = 6377.5 + -4.9 * 650.7601 Δx = 6377.5 + -3188.72449 Δx = 3188.77551The displacement in the y-direction is 3188.78 m at half the time t, meaning that this is the greatest height of the projectile.
Now we can find the horizontal range of the projectile by using the same equation, but this time in the x-direction.
Δx = v_0 t + 1/2at²We will use the x-component of the initial velocity and the acceleration in the x-direction, which is always 0 m/s² assuming air resistance is negligible. Note that the time we have above (25.51 sec) is only half the total time, so we will use double this time (51.02 sec).
Δx = [500 * cos(30)] * 51.02Δx = 22092.31The horizontal range of the projectile is 22092.31 m.
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A 2.0 kg bullet is fired into a sandbag sitting on a wagon. The combined mass of the wagon and the sandbag is 4.5 kg. a) If the wagon/sandbag/bullet moved together with a speed of 0.22 m/s immediately after impact with the bullet, with what speed did the bullet enter the sandbag? b) Is this an elastic or inelastic collision? Explain.
Answer:
To answer your question use the code ICE on here to get your answer works every time for me hope this helps
write any one advantage and disadvantage of eddy current
Explanation:
[tex]advantage[/tex]
It is Sensitivity to surface defects. ...
[tex]disadvantage[/tex]
There is a major heat loss during cycling eddy currents due to friction in the magnetic circuit, especially where the core is saturated
Please mark as brainliest answer
what are the uses of X-rays.
Explanation:
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If you are holding a stack of books at your waist and then you walk across the room your hands did?
1) efficiency
2) power
3) work
4) no work
Answer:
3. Work
Explanation:
Number 1 isn't correct because you are not using efficiency to hold books and walk across the room.
Number 2 could be correct but isn't in this situation because you use power only to hold the books but not to walk across the room.
Number 4 is not correct because you need to do work to do something.
URGENT )If you drive your 1,000 kg car from sea level up to the mountain, which is 366 m above sea level, how much will you have increased your car's potential energy?(consider : g=10m/s2)
1 point
a) 366,000 J
b) 3,660,000 J
c) 2.73 J
d) 20.73 J
Answer:
(B) the increase in the car's potential energy is 3,660,000 J
Explanation:
Given;
mass of the car, m = 1,000 kg
height through the car was drove, h = 366 m
acceleration due to gravity, g = 10 m/s²
The increase in the car's potential energy is calculated as;
P.E = mgh
P.E = 1000 x 10 x 366
P.E = 3,660,000 J
Therefore, the increase in the car's potential energy is 3,660,000 J
Explain the significance of the thermometer, the electric heater, and the power supply.
Answer:
This question appear incomplete
Explanation:
This question appear incomplete. However, the significance/functions of the "instruments" mentioned (in the completed question) can be predicted since these "instruments" generally have specialized function.
A thermometer is used to determine the temperature of a substance or an object. The electric heater uses electricity to produce heat (which can be utilized for different purposes). The power supply is used to supply electricity for instruments/appliances that may require electricity to function.
the multimeter functions as an ammeter
Answer: What?
Explanation:
What is Newton's third law of motion? Give an example.
Answer: Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.
Explanation: hope this helps :)
The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat's average kinetic energy? (1 kJ = 1000 J)
Answer:
69.44kJ
Explanation:
Kinetic energy is expressed as;
KE = 1/2mv^2
m is the mass = 500kg
v is the velocity
Get the velocity;
v = displacement/time
velocity = 2000/120
velcoity = 16.7m/s
Gt the kinetic energy
KE = 1/2 * 500 * 16.7²
KE = 250*277.78
KE = 69,444.4Joules
Since 1000J = 1kJ
69,444.4Joules = 69,444.4/1000
69,444.4Joules = 69.44kJ
Hence the Secretariat's average kinetic energy is 69.44kJ
Answer:C 69.0kJ
Explanation:
The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed along axes of AB and AC. Set F=500N
Answer:
The magnitude will be "353.5 N". A further solution is given below.
Explanation:
The given values is:
F = 500 N
According to the question,
In ΔABC,
⇒ [tex]\angle BCA = (90-30)[/tex]
⇒ [tex]=60^{\circ}[/tex]
then,
⇒ [tex]\angle BAC=(180-45-60)[/tex]
⇒ [tex]=75^{\circ}[/tex]
Now,
The corresponding angle will be:
⇒ [tex]\angle FAC=60^{\circ}[/tex]
⇒ [tex]\angle FAB=70+60[/tex]
⇒ [tex]=135^{\circ}[/tex]
Aspect of F across the AC arm will be:
= [tex]F\times cos(60)[/tex]
On putting the values of F, we get
= [tex]500\times (.5)[/tex]
= [tex]200 \ Newton[/tex]
Component F along the AC (in magnitude) will be:
= [tex]F\times cos(135)[/tex]
= [tex]500\times (-.707)[/tex]
= [tex]-353.5 \ N \[/tex]
A stunt-rider on a motorcycle rides down a ramp and into a vertical loop-the-loop. If the diameter of the loop is 7.50 m, then the slowest speed the motorcycle can have at the top of the loop if it is to remain in contact with the loop is _________ km/h.
Answer:
v = 6.06 m/s
Explanation:
In order for the rider to pass the top of the loop without falling, his weight must be equal to the centripetal force:
[tex]Centripetal Force = Weight \\\frac{mv^2}{r} = mg\\\\\frac{v^2}{r} = g\\\\v = \sqrt{gr}[/tex]
where,
v = minimum speed of motorcycle at top of the loop = ?
g = acceleration due to gravity = 9.8 m/s²
r = radius of the loop = diameter/2 = 7.5 m/2 = 3.75 m
Therefore, using these values in equation, we get:
[tex]v = \sqrt{(9.8\ m/s^2)(3.75\ m)}[/tex]
v = 6.06 m/s
