Answer:
Mantlee
Explanation:
PLS HELP ASAP
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HAPPY HOLIDAYS
Answer:
Displacement is calculated using the following formula: [tex]d = v \times t[/tex]Where v in meters per second is the velocity and t in seconds representing time Hence d = 14,542.32Free fall differs from terminal velocity, in that during free fall
A.
only air resistance is acting on an object
B.
only gravity is acting on an object
C.
air resistance and gravity are acting on an object with unequal magnitudes
D.
air resistance and gravity are acting on an object with equal magnitudes
Answer:
B
Explanation:
HELP ASAP!!!!!!! PLEASE WILL GIVE BRAINLIEST
What is a selectively permeable membrane?????????????
Answer: The plasma membrane is called a selectively permeable membrane as it permits the movement of only certain molecules in and out of the cells. Not all molecules are free to diffuse. If plasma membrane ruptures or breaks down then molecules of some substances will freely move in and out of the cells. Semipermeable membrane describes a membrane that allows some particles to pass through (by size), whereas the selectively permeable membrane "chooses" what passes through (size is not a factor). Selective permeability is a property of cellular membranes that only allows certain molecules to enter or exit the cell. This is important for the cell to maintain its internal order irrespective of the changes to the environment. For example, water, ions, glucose and carbon dioxide may need to be imported or exported from the cell depending on its metabolic activity. Similarly, signaling molecules may need to enter the cell and proteins may need to be released into the extracellular matrix. The presence of a selectively permeable membrane allows the cell to exercise control over the quantum, timing and rate of movement of these molecules.
Explanation: hope this helps you with your work/assingment! Have a wonderful day/night!
If a student is sitting in their chair and the leg of the chair breaks the student will __________ toward the floor because the gravity is a greater force.
A.Accelerate
B.Force
C.Balance
D.Speed
Answer:
theyll accelerate towards the floor :)
please help me on the 1st bullet point for brainliest!
Answer:
thermal energy
Explanation:
What is the kinetic energy of a 0.150 kg
object moving at a velocity of 100m/s?
Answer:
750J
Explanation:
Given parameters:
Mass of the object = 0.15kg
Velocity of the object = 100m/s
Unknown:
Kinetic energy of the body = ?
Solution:
The kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;
K.E = [tex]\frac{1}{2}[/tex] m v²
m is the mass of the body
v is the velocity
Now insert the parameters and solve;
K.E = [tex]\frac{1}{2}[/tex] x 0.15 x 100² = 750J
Dawn and Timothy are sailboating in Lake Obewon. Starting from rest near the shore, they accelerate with a uniform acceleration of 0.39 m/s/s. How far are they from the shore after 18 seconds? *
Answer:
The value is [tex]s =63.18 \ m[/tex]
Explanation:
From the question we are told that
The uniform acceleration is [tex]a = 0.39 \ m/s^2[/tex]
The time considered is [tex]t = 18 \ seconds[/tex]
Generally the from kinematic equation we have that
[tex]s = ut + \frac{1}{2} at^2[/tex]
Given that the boat started from rest , the initial velocity is u = 0 m/s
So
[tex]s = 0 * 18 + \frac{1}{2} *0.39 * 18^2[/tex]
=> [tex]s =63.18 \ m[/tex]
difference between lower fixed point and upper fixed point
Answer:
The lower fixed point, or ice point, is the temperature of pure melting ice at normal atmospheric pressure. The upper fixed point, or steam point, is the temperature of pure boiling water at normal atmospheric pressure.
Explanation:
Describe the water cycle process starting from an afternoon thunderstorm. There are many different variations that could happen.
Explanation:
The water cycle basically involves five steps:
evaporation and transpiration ⇄condensation, ⇄precipitation, ⇄runoff, ⇄infiltration ⇄So when a thunderstorm occurs it helps in completing the precipitation process by enabling the release of water vapor stored up in the atmosphere to fall on the ground as rain.
After this, the water runoffs to the surface of the ground, on plants, into rocks, rivers, and lakes.
Next, the Infiltration process enables the water on the ground surface to enter the soil some of which becomes groundwater.
The cycle begins again as the evaporation and transpiration process begins, where the groundwater as a result of heat from the sun is taken back into the atmosphere, while water in plants by means of transpiration goes back into the atmosphere.
It then condenses and falls back as precipitation again.
The water cycle is the continuous movement of water within the atmosphere and surface and it is described by five major steps.
The given problem is based on the concept of water cycle. The continuous movement of water within the Earth and its atmosphere, is known as water cycle. The water cycle basically involves five steps:
evaporation and transpiration condensation precipitation,runoff infiltrationSo when a thunderstorm occurs it helps in completing the precipitation process by enabling the release of water vapor stored up in the atmosphere to fall on the ground as rain.
After this, the water runoffs to the surface of the ground, on plants, into rocks, rivers, and lakes. Next, the Infiltration process enables the water on the ground surface to enter the soil some of which becomes groundwater.
The cycle begins again as the evaporation and transpiration process begins, where the groundwater as a result of heat from the sun is taken back into the atmosphere, while water in plants by means of transpiration goes back into the atmosphere. It then condenses and falls back as precipitation again.
Thus, we can conclude that the water cycle is the continuous movement of water within the atmosphere and surface and it is described by five major steps.
Learn more about the water cycle here:
https://brainly.com/question/1535846
A wheelchair ramp is 5.2 m long and 0.8 m high. Calculate the ramp’s mechanical advantage
Answer:
5
Explanation:
62
A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
a. How long does it take to reach the ground?
b. How far does the rock land from the base of the cliff?
Answer:
a. t = 2.02 s
b. d = 20.2 m
Explanation:
Horizontal Motion
If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The time the object takes to hit the ground can be calculated as follows:
[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]
The time does not depend on the initial speed.
The range or maximum horizontal distance traveled by the object can be calculated by the equation:
[tex]\displaystyle d=v.t[/tex]
The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.
a.
The time taken by the rock to reach the ground is:
[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]
[tex]\displaystyle t=\sqrt{4.0816}[/tex]
t = 2.02 s
b.
The range is:
[tex]\displaystyle d=10\cdot 2.02[/tex]
d = 20.2 m
A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11- Calculate the magnitude of the acceleration of the car during this 5.0-second time interval.
Answer:
[tex]a=2.4\ m/s^2[/tex]
Explanation:
Given that,
Initial speed of a car, u = 13 m/s
Final speed of a car, v = 25 m/s
Time, t = 5 s
We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2[/tex]
So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].
A billiard ball bangs against a side bumper, giving the ball a speed of 5 m/s. If the
ball has a mass of 0.15 kg, what is the ball's kinetic energy in joules?
Answer:
1.875 joules
Explanation:
K.E=1/2 mv²
K.E=1/2 0.15×5²
K.E=1.875 joules
What is an astronomical unit or AU
Answer:
D
Explanation:
Answer:
Astronomical Unit = 4.8481×10−6 pc; 1.5813×1.
Or even AU = Equal to
Explanation:
A box has a momentum of 38.0 kg*m/s to the right. A 88.3 N force pushes it to the right for 0.338 s. What is the final momentum of the box? (unit = kg*m/s)
Answer:
63.8454kgm/s
Explanation:
According to Newton's second law;
Force = mass ×acceleration
Fore = m(v-u)/t
Force = mv-mu/t
MV is the final momentum
mu is the initial momentum = 38kgm/s
Force = 88.3N
Time = 0.338s
Substitute and get mv
88.3 = mv-38/0.338
88.3×0.338 = mv-38
29.8454 = mv-38
MV = 29.8454+34
mv = 63.8454kgm/s
Hence the final momentum is 63.8454kgm/s
Answer:
67.8
Explanation:
im an acellus student, and this is the answer that i got when doing the problem.
What is the correct answer?
Answer:3
Explanation:
n=Q/e formula of this?
Answer:
Its not just a mere formula . It tells a hell lot about charges .
q = ne . As you know , q stands for charge and e stands for charge on an electron . As for n , it represents an integer.
This whole q=ne thing represents quantisation of charge. The formula tells us that charge is quantized ( in the form of small packets)
Every body on this small earth has a charge which has to be an integral multiple of ‘e’ . So , we represent charge on a body(q) as
q=ne.
Hence the formula .
I hope you got what I want to say .
Thanks for reading .
While riding a skateboard, Nina ran into a rough patch of pavement, but she thought she could ride right over it. Instead, the skateboard
stopped but Nina didn't. Her _______ kept her moving forward, so she fell off the skateboard.
Answer:
ineria
Explanation:
It is due to her inertia of motion that kept her moving forward.
We have Nina who is riding skateboard.
We have to determine why Nina fell off the skateboard on rough pavement.
What is Inertia ?A property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force.
According to the question -
Before the rough patch, Nina was riding smoothly. However as soon as she enters the rough patch, the rough patch acts as an obstruction to the forward movement of skateboard. The skateboard and Nina are both moving with same velocity. The skateboard is in contact with the rough patch and as soon as the skateboard's motion is obstructed, the skateboard comes to rest but due to the inertia of motion, Nina continues to move with the same forward velocity. In this way, Nina falls ahead of skateboard.
Hence, it is due to her inertia of motion that kept her moving forward.
To solve more questions on Inertia, visit the link below-
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A bucket of water experiencing a gravitational force of 525 N is pulled from a water well. Net force in the Y direction is 45 N therefore the magnitude of the force of tension is__ newtons.
Answer:
T = 570 N
Explanation:
Given that,
The gravitational force acting on a bucket of water = 525 N
Net force in the Y direction is 45 N
We need to find the magnitude of the force of tension. It can be calculated as :
45 = T - 525
T = 525 + 45
T = 570 N
Hence, the force of tension is 570 N.
Answer:
570N
Explanation:
what is the correct answer?
Answer:
3.2
Explanation:
I remember taking this quiz and I think that one is correct
your stopped at a red light. You've checked the intersection to see that it is clear of vehicles and pedestrians, unless a tells you not, you may then?
Answer:
Unless you are at a red light you may not proceedYou pose a threat to other drivers who are following the instructions and ethics.A ball of Mass M is swung in a vertical circle with a constant tangential speed. Figure 1 shows the forces exerted on the ball at the top of the circle, and Figure 2 shows the forces exerted on the ball at the bottom of the circle. Which of the following is an expression for the centripetal acceleration of the ball in terms of M, T1, T2, and any fundamental constants?
Answer:
T1+T2/2M
Explanation:
The expression for the centripetal acceleration for the vertical circle is [tex]a_c = \frac{T_1 + T_2 }{2m}[/tex].
In a vertical circular motion, the tension of the swing at the top of the circle is given as;
[tex]T_1 =m a_c_{top} - mg\\\\T_1 = ma_c - mg\\\\mg = ma_c - T_1[/tex]
The tension of the swing at the bottom of the circle is given as;
[tex]T_2 = ma_{bottom} + mg\\\\T_2 = ma_c + mg[/tex]
solve the two equations together;
[tex]T_2 =ma_c + ( ma_c -T_1)\\\\T_2 = ma_c + ma_c - T_1\\\\T_2 + T_1 = 2ma_c\\\\a_c = \frac{T_1 + T_2}{2m}[/tex]
Thus, the expression for the centripetal acceleration for the vertical circle is [tex]a_c = \frac{T_1 + T_2 }{2m}[/tex].
Learn more here:https://brainly.com/question/14881568
Which phrase describes blackbody radiation?
O A. Radiation that is absorbed by an object as it warms
O B. Light given off by an object based on its temperature
O C. Radiation that explains the wave model of light
O D. Light given off by an object based on its color
Answer:
b
Explanation:
The phrase that describes blackbody radiation is the radiation that is absorbed by an object as it warms.
What is blackbody radiation?Blackbody radiation is a radiation produced by heated objects, particularly from a blackbody.
In physics, a blackbody, approximated by a hole in a hollow black sphere, absorbs all incident electromagnetic radiation and reflects none.
Therefore, the phrase that describes blackbody radiation is the radiation that is absorbed by an object as it warms.
Learn more about blackbody radiation at: https://brainly.com/question/13934832
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De-Broglie postulated that the relationship, lambda=h/p is valid for relativistic particles. Find out the de-Broglie wavelength for an electron whose kinetic energy is 3MeV.
Given :
An electron with kinetic energy of 3 MeV.
To Find :
The de-Broglie wavelength for that electron.
Solution :
We know, de-Broglie wavelength for an electron with kinetic energy K.E is given by :
[tex]\lambda = \dfrac{h}{\sqrt{2m(K.E)}}[/tex]
Putting all given values in above equation, we get :
[tex]\lambda = \dfrac{6.626\times 10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times 3\times 10^6 \times 1.6\times 10^{-19}}}\\\\\\\lambda = 7.089 \times 10^{-13} \ m[/tex]
Hence, this is the required solution.
You’ve been in a car traveling at 80 km/hr. How many hours will it take to travel 640 km?
Which of these waves has the greatest wavelength? Group of answer choices Wave shown with 2 wavelengths. Wave shown with 3 wavelengths. Wave shown with 1 wavelength stretch over a short distance. Wavelength shown with 1 wavelength stretched over a long distance.
Answer:
This question is incomplete
Explanation:
This question is incomplete because of the absence of the figure. However, wavelength can be described as the distance between two crests (identical points) of a wave (as illustrated in the picture attached). Thus, a wave with a large/great wavelength must have a long distance between the two crests and has nothing to do with the number of crests/wavelengths since distance between crests could also be small.
Hence, what appears to be the correct option is the last option (Wavelength shown with 1 wavelength stretched over a long distance).
Answer:
Its B.
Explanation:
Im took the exam.
Two objects, one 4 times as massive as the other, are approaching each other under their mutual gravitational
attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 1 m/
s2. When the separation between them is 25 km, the acceleration of the heavier object is
To Find :
The acceleration of the heavier object.
Solution :
Force of gravitation on lighter object by heavier object is :
[tex]F = \dfrac{Gm(4m)}{100^2}[/tex]
Acceleration of lighter object is given by :
[tex]a_s = \dfrac{4Gm}{100^2}\\\\m = \dfrac{50^2}{G}[/tex] .....1)
Now, acceleration of heavier object when separation between them is 25 km :
[tex]4ma_h = \dfrac{Gm(4m)}{25}\\\\a_h = \dfrac{Gm}{25}[/tex].....2)
Putting value of m in equation 2, we get :
[tex]a_h = \dfrac{G\times 50^2}{G \times 25}\\\\a_h = \dfrac{2500}{25}\\\\a_h = 100\ m/s^2[/tex]
Therefore, the acceleration of the heavier object is 100 m/s².
A container of height 30cm has a capacity of 1.5litres. What is the height of similar container of capacity 3m^3.
Answer:
Height = 378 cmExplanation:
see image
A ball is thrown vertically upward with a speed v. An identical second ball is thrown upward with a speed of 1/2 v (half as fast). What is the ratio of the maximum height of the second ball to that of the first ball
Answer:
1:4
Explanation:
The formula for calculating the maximum height of the ball is expressed as;
H = u²sin²theta/2g
If a ball is thrown vertically upward with a speed v, its maximum height is expressed as;
H = v²sin²90/2g
Since sin90 = 1
H = v²/2g.... 1
If an identical second ball is thrown upward with a speed of 1/2 v, then the maximum height will be expressed as;
H1 = (1/2v)²sin²90/2g
H1 = (v²/4)(1)/2g
H1 = v²/8g ...... 2
Divide both equations
H/H1 = (v²/2g)/(v²/8g)
H/H1 = v²/2g × 8g/v²
H/H1 = 8g/2g
H/H1 = 4
Reciprocate both sides
H1/H = 1/4
H1:H = 1:4
Hence the ratio of the maximum height of the second ball to that of the first ball is 1:4
Neeeee rnnnn ASAP offering 55 points CER: Brielle pushes a shopping cart through the store with an acceleration of 2
m/s2. The mass of the shopping cart with the groceries in it is 22 kg. Guiding
Question: How can Brielle increase the acceleration of the shopping cart?
Answer:
Decease the mass
Increase the force applied
Explanation:
To increase the acceleration of the shopping cart, Brielle should reduce the load inside her cart.
According to Newton's second law of motion;
Force = mass x acceleration
Now, mass is indirectly proportional to the acceleration. The more the mass, the lower the acceleration a body will generate.
Lighter bodies moves with a faster acceleration.
In this case the force applied is constant.
If the force applied is also, increased the acceleration of the body will increase also.
